What is the mass of one mole of the following compounds?
i) H2SO4
ii) Al(OH)3
With working aswell please :)
2007-12-29 21:59:26 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Some working too?
2007-12-29 22:24:04 · update #1
H2SO4 the exact mass of in one mole is:
1.01(2)+32.067+16.00(4)= 98.087g
and for Al (OH)3 is:
26.98+16.00(3)+1.01(3)= 78.01g in exact up to the decimal points
2007-12-30 03:28:53 · answer #1 · answered by Dexter Vile L 1 · 0⤊ 0⤋
H2SO4 = 2*1+1*32+4*16=2+32+64=98g
Al (OH)3 = 27+ 3* (16+1) = 27+51=78
2007-12-29 22:58:22 · answer #2 · answered by Ahtisham 1 · 0⤊ 0⤋
H2SO4 = 2*1+1*32+4*16=2+32+64=98g
Al (OH)3 = 27+ 3* (16+1) = 27+51=78
2007-12-29 22:23:57 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
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2016-05-17 13:25:06 · answer #4 · answered by Anonymous · 0⤊ 0⤋
a million. Mass and moles of anhydrous compound sixty 9.sixty 4 g - sixty seven.sixty 5 g = _______ _______ x a million mol / 159.6 g = _______ mol CuSO4 2. Mass and moles of water 70.seventy 4 g - sixty 9.sixty 4 g = ________ _______ x a million mol / 18.0 g = ________ mol H2O 3. Divide ans (2) via ans (a million)
2016-11-26 20:11:07 · answer #5 · answered by ? 4 · 0⤊ 0⤋
1. 98g/mol
2. 78g/mol
2007-12-29 22:03:14 · answer #6 · answered by Anonymous · 0⤊ 0⤋