The center of a circle is at (1,3). If the circle passes through he point (4,7), find the length of the radius of the circle?
2007-12-29 17:24:21 · 8 answers · asked by veronika 1 in Science & Mathematics ➔ Mathematics
r ² = (4 - 1) ² + (7 - 3) ²
r ² = 9 + 16
r = 5
2007-12-29 18:11:51 · answer #1 · answered by Como 7 · 1⤊ 1⤋
The equation of a circle with centre at point (a,b) and radius r is given by: (x - a)^2 + (y - b)^2 = r^2 For the given circle a = 1 and b = 3. For the point (4,7) x = 4 and y = 7. Hence: (4 - 1)^2 + (7 - 3)^2 = r^2 => 9 + 16 = r^2 => r = sqrt(25) = 5 Answer: the radius is 5 (units of length) =
2016-05-27 23:49:44 · answer #2 · answered by ? 3 · 0⤊ 0⤋
a^2+b^2=c^2
If you make a triangle on the graph, the radius will be c
The rise would be a and the run would be b
(1,3) to (4,7)
4-1=3
7-3=4
(3)^2+(4)^2=c^2
9+16=c^2
25=c^2
c=5
The length of the radius is five
2007-12-29 20:35:56 · answer #3 · answered by Michelle M 2 · 0⤊ 1⤋
distance between those points is
sqrt((1-4)^2 + (7-3)^2) = 5
2007-12-29 17:27:26 · answer #4 · answered by hankbeasley 1 · 1⤊ 2⤋
YOu can use pythagorean theorem
radius = sqrt{(4-1)^2 + (7-3)^2} = sqrt{3^2 + 4^2) = 5
2007-12-29 17:40:13 · answer #5 · answered by Anonymous · 0⤊ 3⤋
It is the distance between ( 1, 3) and (4, 7). It is too simple a question for asking on Yahoo Answers.
2007-12-29 17:27:46 · answer #6 · answered by Madhukar 7 · 1⤊ 6⤋
sqrt(7-3)^2+(4-1)^2
SQRT16+9=5
2007-12-29 17:31:12 · answer #7 · answered by someone else 7 · 0⤊ 4⤋
Wow, you're one lazy kid. Use the distance formula. Seriously, are you even trying?
2007-12-29 17:37:53 · answer #8 · answered by bigDee 2 · 1⤊ 3⤋