Algebra question, help please?

Question

Any idea how to write this equation, any help appreciated. Thanks!!!

Use the given conditions to write an equation for the line in slope-intercept form.
Passing through ( -3, -4) and ( -6, -5)

Answer 1

m = (- 5 + 4) / (- 6 + 3)
m = (- 1) / (- 3)
m = 1 / 3
y + 5 = (1/3) (x + 6)
y + 5 = (1/3) x + 2
y = (1/3) x - 3

Answer 2

first calculate the slope, m = (change in y)/(change in x)

m = (-4 - -5)/(-3 - -6) = (1/3) = m

calculate the y intercept (b), by plugging either one of the given x-y pairs into the general form of a linear equation, y =mx + b.

-4 = (1/3)*-3 + b
b = -3

thus the equation would be y = (1/3)*x - 3.

you can verify that this works by plugging in the x value (-6) from the second point, and seeing if the equation calculates the correct y-value.

y = (1/3)*(-6) -3
y = -5

which is the y-value of the second point.

Answer 3

The first step is to find the slope (which is usually represented by m). The slope formula is
m = (y2 - y1)/(x2 - x1)
where x1 = -3, y1=-4, x2=-6, and y2 = -5.
Thus the slope is
m = (-5 - (-4))/(-6 - (-3))
m= (-5+4)/(-6+3)
m=-1/3
So, the slope is -1/3
The next step is rather simple. You simply apply the formula
y - y1 = m(x - x1)
When you put in the appropriate values, you should get this
y = (1/3)x - 3

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Answer 4

x step is 3 (-3-(-6))
y step is 1
so slope is 1/3
y = 1/3x + n
y = 1/3 -3 +n = -1 +n
-4 = -1 + n
n = -3
y= 1/3 x -3
test
-5 = 1/3(-6) -3
-2 = -6/3 = -2
so that works

Answer 5

y=1/3x-3

You have to plot the two points on the graph and then you'll be able to find the slope(rise over run.) Then you find the y-intercept
by finding the point the line crosses the y-axis. Then u plug the
slope and the y-intercept into the equation y=mx+b.
M=slope
B=y-intercept

Answer 6

line through (--3, --4) and (--6, --5) is
y + 5 = (-- 4 + 5) / ( -- 3 + 6) (x + 6)
Or y = (1/3)x -- 3
slope = 1/3, y-intercept = -- 3

Answer 7

point slope formula:
y - y1 = m * (x - x1)

(x,y) = (-3,-4)
(x1,y1) = (-6,-5)

y - y1 = m * (x - x1)
-4 - (-5) = m * (-3 - (-6))
-4 + 5 = m * (-3 + 6)
1 = m * 3
m = 1/3

slope = 1/3

let y-intercept be at (x2,y2), or (0,y2)

use point slope formula
y - y2 = m * (x - x2)
-4 - y2 = (1/3) * (-3 - 0)
-4 - y2 = -1
y2 = -3

y-intercept = -3

y = m*x + b
y = (1/3)*x - 3

Answer 8

m=(-5+4)/(-6+3)=3
immediately we can write y=3x+b
substitube (-6,-5)
-5=-18+b
b=13
y=3x+13