hey im having trouble with a maths question can u help me out?

Question

ok there is a really hard question that im trying to solve and i need ur help it is:

1/sqrt3 + sqrt3

guys plz show ur full working thx

and another question is 4sqrt3 + 2/sqrt3

oh and btw steve u got it right i know the answer i just need to know how to work it out

Answer 1

1/sqrt3 + sqrt3

Find the lowest common denominator for both terms, in this case sqrt3, so we get
=1/sqrt3 + sqrt3
=1/sqrt3 + (sqrt3)(sqrt3)/ sqrt3
=1/sqrt3 +3/sqrt3
=4/sqrt3

Answer 2

there are some things you never want in the denominator of your final answer: negative, sqrt, fraction, imaginary number

So, how do you get sqrt3 out of the denominator? multiply top and bottom by sqrt3
1/sqrt3 = sqrt3/3

sqrt3 / 3 + sqrt3 = 4sqrt3 / 3

second question:
4sqrt3 + 2/sqrt3
again multiply by sqrt3/sqrt3 to get the sqrt3 out of the denominator
2/sqrt3 = 2sqrt3 / 3
4sqrt3 = 12sqrt3 / 3 (putting both over 3)
4sqrt3 + 2/sqrt 3 = 12sqrt3 / 3 + 2sqrt3 / 3 =
14sqrt3 / 3

Answer 3

a million. 19w + w = 20c 19w + w = 20c (upload 19w and 1w on an identical time) 20w = 20c (divide the two factors by 20) w = c that's the end result, that w is equivalent to c, now no longer some thing greater advantageous could be gained. we don't have sufficient innovations to be sure the values of w or c, or the two. 2. 9x - x - 5 = 11 9x - x - 5 = 11 (do away with 1x from 9x) 8x - 5 = 11 (upload 5 to the two factors) 8x = sixteen (divide the two factors by 8) x = 2 we've worked out top right here that the cost of x is two. 3. 2y + y + 2 = 7 2y + y + 2 = 7 (upload 2y and 1y on an identical time) 3y + 2 = 7 (do away with 2 from the two factors) 3y = 5 (divide the two factors by 3) y = 5/3 or y = a million 2/3 you purchased this very final one desirable. the cost of y is a million 2/3. only save practising, do a great form of questions, that's what I did at your age and without delay grew to grow to be into able to do those questions with none challenge.

Answer 4

1/√3 + √3 = {1 + (√3)(√3)} / √3 = (1+3) / √3 = 4/√3