A) 3x + y = –1
B) 9x + 3y = –3
Multiply B by 1/3 and you get
C) 3x + y = -1
Therefore, Equation (A) = Equation (B) And you only have one equation with two unknowns... Can't be solved.
2007-12-29 14:37:06
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answer #1
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answered by gugliamo00 7
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Hi,
3x + y = –1
9x + 3y = –3
To solve by addition, multiply the first equation by -3 and add them together. The x term will drop out.
-3(3x + y = –1)
9x + 3y = –3
-9x - 3y = 3
9x + 3y = –3
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0 = 0
This time both variables dropped out, giving a true identity. Since 0 always equals zero, then the lines intersect at every point on either equation. they are actually the same equation in slope-intercept form, so there are an infinite number of points that are the solution to this system.
I hope that helped!! :-)
2007-12-29 14:39:49
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answer #2
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answered by Pi R Squared 7
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PLEASE REWRITE YOUR 2 EQUATIONS.
With what you have right now, it does not seem likely that there is as solution to the question you are being asked.
OTHERWISE, going with what you gave us:
3x + y = –1
Multiply this equation by 3 to you can solve, so
(3x + y = –1)*3
9x + 3y = -3
You can see this is the same as the second equation, so any value of x and y works, thus, there is an unlimited amount of solutions.
9x + 3y = -3 (1st equation)
9x + 3y = –3 (2nd equation)
2007-12-29 14:32:40
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answer #3
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answered by ¿ /\/ 馬 ? 7
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3x+y=-1
9x+3y=-3
i dont see how u wud solve this by addition.
but, we can use other methods to solve for x and y.
3x+y=-1
9x+3y=-3
now, we can see very easily that the first equation=3*the second equation.
from the first equation, we know:
3x+y=-1
y=-1-3x
y=-(3x+1)
inputting this in the second results to:
9x+3(-(3x+1))=-3
9x-3(3x+1)=-3
9x-9x-3=-3
-3=-3
this means that the equation cannot be solved, because as i said, the second equation is basically 3* the first. please check ur equations to make it possible to solve.
sorry.
2007-12-29 14:41:30
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answer #4
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answered by Harris 6
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3x + y = - 1
y = - 1 - 3x
9x + 3y = - 3
3x + y = - 1
y = - 1 - 3x
There seems to be no solution to this problem.
2007-12-29 14:54:50
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answer #5
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answered by Jun Agruda 7
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