Need Help on Balancing Equations!!!!!!?

Question

What are the balanced equations for the following two reactions:
1.) copper (II) sulfate + iron --> copper + iron (II) sulfate
2.) copper (II) sulfate + iron --> copper + iron (III) sulfate

Answer 1

First, you need to know the charges on the ions:
copper (II) = +2; copper (III) = +3; iron (II) = +2; iron (III) = +3; sulfate = -2.

Determine the compounds, making sure that the charges balance to zero:
Copper (II) Sulfate: Cu(+2), SO4(-2) = CuSO4
Iron (II) Sulfate: Fe(+2), SO4(-2) = FeSO4
Iron (III) Sulfate: Fe(+3), SO4(-2) = Fe2(SO4)3

Next, write the unbalanced equations using the chemical formulas:
CuSO4 + Fe --> Cu + FeSO4.
CuSO4 + Fe --> Cu + Fe2(SO4)3

Now, make sure you have the same number of atoms on each side of the equation. The first one is easy, because it is already balanced.

The second one however is not balanced.
Start by balancing the ion most out of balance, which is sulfate. There is only one in the reactants but 3 in the product:
3 CuSO4 + Fe --> Cu + Fe2(SO4)3
Repeat for the most out of balance atom, which is now copper:
3 CuSO4 + Fe --> 3 Cu + Fe2(SO4)3
Now balance the iron:
3 CuSO4 + 2 Fe --> 3 Cu + Fe2(SO4)3
And you're done.

Answer 2

1.) CuSO4 + Fe ===> Cu +FeSO4

2.) 3CuSO4 + 2Fe ===> 3Cu + Fe2(SO4)3

Answer 3

ha im in 7th grade and we just learned these and yet i have no clue sorry i cant help

Answer 4

CuS + Fe2+ --------- FeS + Cu2+
3CuS + 2Fe3+ ---------- Fe2S3 + 3Cu2+