What is y=3/4x + 3 in standard form [ax+by=C]?

Question

i Just need the answer but it would be kind to explain how you got it..

=]

i meant

y = 3/2x + 3

in standard form

PLEASE HELpp

i JUSt need the Answer...buh details would help

Answer 1

y = 3/2x + 3 (times both sides by 2)

2y = 3x + 6 (subtract both sides by 3x)

-3x + 2y = 6 and there you have it, it's in standard form!

Answer 2

replace the slope and the given factor for y - y1 = m(x - x1) and convert that into Ax + by = C, the place Ax is constructive integer and B and C are integers. y - 4 = (-3/4)(x - (-2)) y - 4 = (-3/4)(x + 2) y - 4 = (-3x/4) - (3/2) . . . . Distribute -3/4 into x + 2. 4y - sixteen = -3x - 6 . . . . . . . Multiply each term by 4. 4y + 3x - sixteen = -6 . . . . . . .upload the two sides by 3x. 4y + 3x = sixteen - 6 . . . . . . . upload the two sides by sixteen. 3x + 4y = 10 . . . . . . . . . .this is the respond (do not complication with regard to the ten. that's the dazzling value for Ax + by = C style). i'm hoping this helps!

Answer 3

y= (3/2) x + 3
(Moving (3/2) x to the left side)
-(3/2) x + y = 3
(Comparing with ax + by = c)

Answer = a= -3/2; b= 1, c=3.
Simple.

Answer 4

y = 3/2x + 3
first clear the fraction by multiplying all three terms by the denominator 2

2y = 3x + 6

subtract 3x over to left side

-3x + 2y = 6

normally it is preferred to have the x term positive, so multiply through the equation by -1

3x - 2y = -6

Answer 5

All you need to do is move the x and y to the same side of the equation.

y = (3/2)x + 3

Subtract (3/2)x from both sides, because you have to do the same thing to both sides of the equation, and you get:

-(3/2)x + y = 3

A= -(3/2)
B= 1
C= 3

Answer 6

Assume question is:-
y = (3/2) x + 3
2y = 3x + 6
3x - 2y = - 6

Answer 7

y = 3/4x + 3
4/3(3/4x - y) = 4/3(- 3)
x - 4/3y = - 4