i need help with algebra 2....its so hard and fustrating...i suck at math period?

Question

5y+2 2x-4
------ + -------
xy^2 4xy


adding and subtracting rational expressions...i dont get any of this rational expresion crap...its so hard...i want to punch myself


im only in 10th grade

Answer 1

Don't worry! study, get extra help..do extra credit. Your life's not over unless you wanted to be quantum physicist or something math related. In high school math was the only subject I was bad in. Yet I am surviving college...

Answer 2

5y+2 2x-4
------ + -------
xy^2 4xy

The fractions need to have a common denominator to add them. One denominator is xy^2 and the other is 4xy. So you need to multiply the first fraction by 4 and the second by y.

(5y+2) / xy^2 + (2x-4)/4xy =
4(5y+2) / 4xy^2 + y(2x-4) / 4xy^2 =
(20y + 8) / 4xy^2 + (2xy - 4y) / 4xy^2 =
[(20y + 8) + (2xy - 4y)] / 4xy^2 =
(2xy + 16y + 8) / 4xy^2 =
(xy + 8y + 4) / 2xy^2

Answer 3

.) 2 3/4 - 11/4=0 2.) An athlete recovering from an accident needs to walk 15 kilometers each day for 5 weeks. Today she walked 4 3/4 kilometers the first hour and 2 1/2 kilometers the second hour. How much farther does she need to walk today? 7.75km

Answer 4

(5y + 2)/(xy^2) + (2x - 4)/(4xy)

Use the same approach we learned in elementary school when adding fractions

the LCD needs each factor in the denominators the most times it occurs in any denominator

LCD = 4xy^2

[4(5y + 2)]/(4xy^2) + [y(2x - 4)]/(4xy^2)

(20y + 8 + 2xy - 4y)/(4xy^2)

(16y + 2xy + 8)/(4xy^2)

(8y + xy + 4)/(2xy^2)

Answer 5

multiply the first fraction by 4/4, which is ok since it is really 1.

(4/4)(5y+2)/(xy^2)

(20y+8)/(4xy^2)

multiply the second fraction by y/y

(2xy-4y/4xy^2)

now the denominators are the same so you can add easily:

(2xy+16y+8)/(4xy^2)

simplify

(xy+8y+4)/(2xy^2)

Answer 6

16

Answer 7

(5y + 2) / xy^2 + (2x -- 4) / 4xy

= 5y/xy^2 + 2/xy^2 + 2x/4xy -- 4/4xy

= 5/xy + 2/xy^2 + 1/2y -- 1/xy

= 4/xy + 2/xy^2 + 1/2y

= (8y + 4 + xy) / 2xy^2

Answer 8

easy

You have to first get a common denomatior and the multiply by whatever you need to make each denomatior the same then add.

common denomatior: (xy^2)(4xy)
multiply the first one by 4xy
multiply the second by xy^2

it should look like this:

(5y+2)(4xy) + (2x-4)(xy^2)
------------------------------------
(xy^2)(4xy)

Answer 9

5/x

Answer 10

5y+2 2x-4
------ + -------
xy^2 4xy

20y + 8 + 2xy - 4y
= ---------------------------
4xy^2

16y + 2xy + 8
= ----------------------
4xy^2

8y + xy + 4
= ------------------
2xy^2