2007-12-29 07:54:24 · 11 answers · asked by ppd232 1 in Science & Mathematics ➔ Mathematics
6x^2 + 10x +4= 0
(6x+4)(x+1) = 6x^2 + 10x +4 = 0
Take each case, so
6x+4 =0
6x = -4
x= -4/6 = -2/3
x+1=0
x=-1
Answers are therefore when x= -2/3 , -1
2007-12-29 07:58:18 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0⤊ 0⤋
6x² + 10x + 4 = 0
Common factor
2(3x² + 5x + 2) = 0
The middle term inside the parenthesis is + 5x
Find the sum of the middle term
inside the parenthesis, Multiply the first 3 times the last term 2 equals 6 and factor
Factors of 6
1 x 6
2 x 3. . .←. .Use these factors
+ 3x and + 2x satisfy the sum of the middle term
insert + 3x and + 2x into the equation
2(3x² + 5x + 2) = 0
2(3x ² + 3x + 2x) = 0
Group factor inside the parenthesis
2(3x² + 3x) + (2x + 2) = 0
2[3(x + 1) + 2(x + 1)] = 0
2(3x + 2)(x + 1) = 0
- - - - - - - -s-
2007-12-29 08:31:17 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
6x^2+10x+4=0
(2x+2) (3x+2)
Because 2 and 3 go into 6 then distribute the x
You can check with FOIL method
Solve for X:
2x+2=0 3x+2=0
-2 -2 -2 -2
2x/2 -2/2 3x/3 -2/3
x= -1 x=-2/3
2007-12-29 08:24:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The key to factoring quadratics is to find two numbers whose sum or difference (sum, in this case) is 10 and whose product is 24. The numbers are 4 and 6, so the constant terms in the factors will be these numbers. A bit of experimenting then gives the factors as (6x+4)(x+1). From here, proceed as other responders have done.
2007-12-29 08:02:50 · answer #4 · answered by Anonymous · 0⤊ 0⤋
6x^2 + 10x +4 = (3x+2)(2x+2)
x = -2/3 or -1
2007-12-29 07:59:15 · answer #5 · answered by MartinWeiss 6 · 0⤊ 0⤋
6x^2 + 10x + 4 = 0
divide by 2
3x^2 + 5x + 2 = 0
3x^2 + 3x + 2x + 2 = 0
3x(x + 1) + 2(x + 1) = 0
(x + 1)(3x + 2) = 0
x+1 = 0 or 3x + 2 = 0
x = -1 or -2/3
2007-12-29 08:00:31 · answer #6 · answered by mohanrao d 7 · 0⤊ 0⤋
(2x+2)(3x+2)=0
2x+2=0 3x+2=0
these are the two answers:
x= -1 x= -2/3
2007-12-29 08:07:02 · answer #7 · answered by Anonymous · 0⤊ 0⤋
h^2+10h=-21 +21 h^2+10h+21=0 (h+7 ) ( h+3 ) h+7=0 h+3=0 h=-7 h=-3 -------------------- 2x^2-7x-9=0 (2x -9 ) (x +a million ) 2x-9=0 x=-a million 2x=9 x=9/2 -------------------- 3m^2-5m=-2 3m^2-5m+2=0 (3m- 2 ) (m-a million) m=2/3 m=a million its annoying to describe the thank you to do it..
2016-11-26 01:37:23 · answer #8 · answered by Anonymous · 0⤊ 0⤋
This equation is of form ax2+bx+c
a = 6 b = 10 c = 4
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-10 +/-sqrt(10^2-4(6)(4)]/(2)(6)
discriminant is b^2-4ac =4
x=[-10 +sqrt(4)] / (2)(6)
x=[-10 -sqrt(4)] / (2)(6)
x=[-10+2] / 12
x=[-10-2] / 12
The roots are -0.666 and -1
2007-12-29 08:06:15 · answer #9 · answered by cidyah 7 · 0⤊ 0⤋
(6x+4)(x+1)
2007-12-29 08:02:32 · answer #10 · answered by ? 5 · 0⤊ 0⤋