how do I solve this by factoring -5x^2 + 22x - 8 =0?

Answer 1

5 x ² - 22 x + 8 = 0
(5x - 2) (x - 4) = 0
x = 2 / 5 , x = 4

Answer 2

Make a side sum.:-
The factors of 5 are
5 x 1 = 5
Factors of 8 are
8 x 1 = 8
4 x 2 = 8

From these multiplies chose four numbers two from the bottom and two from the top; first multiply and then add to arrive at 22.
The four numbers are 5,4,2, & 1.
Multiply 5 x 4 = 20
& 2 x 1 = 2
Add 20 + 2 = 22
So the four numbers are 5,4,2& 1

(-5x + 2)(x - 4) = 0

-5x + 2 = 0
-5x = -2
x = -2/-5 = 2/5

& x - 4 = 0
x = 4

Answer 3

-5x^2 + 22x - 8 =0
(-5x+2)(x-4)=0
-5x+2=0 x-4=0
x=2/5 and 4

I find the factors of -5 and -8 that add up to 22.
Then, I set each binomial to zero.
Simplify.

Answer 4

-5x^2 + 22x - 8 = 0

5x^2 - 22x + 8 = 0

5x^2 - 20x - 2x + 8 = 0 {rewrite for grouping}

5x(x - 4) - 2(x - 4) = 0

(5x - 2)(x - 4) = 0

x = 2/5, 4

Answer 5

you can factor it to (5x-2)(-x+4)
then you'll get x = 2/5 and 4 :)

Answer 6

This equation is of form ax2+bx+c
a = -5 b = 22 c = -8
x=[-b+/-sqrt(b^2-4ac)]/2a]
x=[-22 +/-sqrt(22^2-4(-5)(-8)]/(2)(-5)
discriminant is b^2-4ac =324
x=[-22 +sqrt(324)] / (2)(-5)
x=[-22 -sqrt(324)] / (2)(-5)
x=[-22+18] / -10
x=[-22-18] / -10
The roots are 0.4 and 4

Answer 7

0.4, 4