Find the limit: lim x->∞ 2x^4+6x^2+5/3+x^3
2007-12-29 06:43:39 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it's +∞
2007-12-29 06:46:33 · answer #1 · answered by Anonymous · 0⤊ 0⤋
After plugging in â for x we obtain â/â or undefined, thus the next step is to divide through by x^3 obtaining
(2x + 6/x + 5/x^3)/(3/x^3 + 1) which yields:
(2*â + 0 + 0)/(0 + 1), or a final answer of:
â.
2007-12-29 15:04:58 · answer #2 · answered by RODNEY_LEE 4 · 0⤊ 0⤋
Use L'Hospitals Rule
= lim x->â (8x^3+12x)/(3x^2)
= lim x->â (24x^2+12)/6x
= lim x->â (48x/6 )
= lim x->â (8x) = â
2007-12-29 06:51:47 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
the limit does not exist.
2007-12-29 06:46:27 · answer #4 · answered by eeeelisabeth<3 2 · 0⤊ 0⤋
i learned limits and im not even in calc yet.. wow.
2007-12-29 16:49:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
dont know
2007-12-29 06:46:41 · answer #6 · answered by momma`````` 2 · 0⤊ 0⤋