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area of an isoseceles traingle wid one side 'x' is

2007-12-29 05:13:47 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

If one of the equal sides is x, and base is b, Then height = sqrt(s^2-(b/2)^2). Thus area = b sqrt(s^2-(b/2)^2)/2
= bsqrt(4s^2-b^2)/4

2007-12-29 05:29:49 · answer #1 · answered by ironduke8159 7 · 0 0

You have not given enough information to determine even an expression for the area

2007-12-29 05:23:11 · answer #2 · answered by kindricko 7 · 0 0

You would need to know the length of the other side of the triangle.

2007-12-29 05:22:47 · answer #3 · answered by Math Wizard 3 · 0 0

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