2007-12-29 04:54:27 · 8 answers · asked by dumbdumb83 1 in Science & Mathematics ➔ Mathematics
Hi,
For this problem, we need to use the FOIL Method which stands for:
First
Outer
Inner
Last
Therefore, we will be multiplying the following:
( [x][x] ) + [ -2x ] + [ 5x ] + [ -10 ]
Now, simplify the above expression to get:
x ^ 2 + 3x - 10 <==== FINAL ANSWER
I hope that helps you out! Please let me know if you have any other questions!
=)
2007-12-29 05:03:50 · answer #1 · answered by The VC 06 7 · 0⤊ 0⤋
Multiply the brackets out:
x*x -2x+5x-(5x2)
= x^2 +3x - 10
2007-12-29 05:00:33 · answer #2 · answered by mr_maths_man 3 · 1⤊ 1⤋
First Outter Inner Last
or
FOIL
(x times x) + (x times -2) + (5 times x) + (-2 times 5)
x² + (-2x) + 5x + (-10)
x² + 3x - 10
2007-12-29 04:59:48 · answer #3 · answered by nekidasajaybird 4 · 1⤊ 1⤋
use the FOIL method:
x^2+5x-2x-10
x^2+3x-10
FINAL ANSWER: x^2+3x-10
2007-12-29 05:19:32 · answer #4 · answered by roxane33 4 · 0⤊ 0⤋
(x+5)(x-2)
x^2-2x+5x-10
x^2+3x-10
2007-12-29 06:49:12 · answer #5 · answered by P.Ariel 3 · 1⤊ 0⤋
oh this is one where you have to foil (first, outside, inside, last)
That describes what you have to multiply
First (x)(x)= x^2
Outside (x)(-2)=-2x
Inside (5)(x)=5x
Last (5)(-2)=-10
x^2+3x-10
2007-12-29 05:01:51 · answer #6 · answered by Shh...I'm batman 2 · 1⤊ 1⤋
x^2 +3x -10.
2007-12-29 06:07:30 · answer #7 · answered by Sasi Kumar 4 · 0⤊ 0⤋
x^2+5x-2x-10
x^2+3x-10
2007-12-29 04:58:35 · answer #8 · answered by Dave aka Spider Monkey 7 · 1⤊ 1⤋