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sqrt of -3 divided by sqrt of 25

how would I simplify

2007-12-29 04:33:13 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Hi,
..__
√-3
------- =
...__
√25

..._
i√3
------ <== ANSWER
..5

I hope that helps!! :-)

2007-12-29 04:38:59 · answer #1 · answered by Pi R Squared 7 · 1 1

Hi,

For this question, you need to notice that the square root of -3 is not a perfect square and is not a real number. Therefore, the numerator becomes i times square root of 3.

Next, we now need to look at the denominator and remember that the square root of 25 is a real number, 5 and -5. (Remember: 5 x 5 = 25 AND -5 x -5 = 25). Now, we would notate this in the final answer using a + / - symbol.

Notice that I've simplified the numerator and denominator separately to get:

FINAL ANSWER: [ i sqrt. 3 ] / [ + / - 5 ]

I hope that helps you out! Please let me know if you have any other questions!

=)

2007-12-29 12:49:29 · answer #2 · answered by The VC 06 7 · 0 1

Factor the radicand of √(-3) into √(-1*3), then take the square roots of the factors:

√(-3)/√25 = √(-1*3) / √25
= √(-1) * √3 / √25
= i √3 / 5
= (i/5)√3

2007-12-29 12:39:12 · answer #3 · answered by DWRead 7 · 1 1

sqrt(-3) / sqrt(25) = sqrt(3)i / 5

2007-12-29 12:39:00 · answer #4 · answered by mohanrao d 7 · 1 1

√-3 = √3i and √25 = 5 so the answer is √3i/5.

2007-12-29 12:41:31 · answer #5 · answered by steiner1745 7 · 0 2

hah its 5... like everyone else said!!!

2007-12-29 12:41:26 · answer #6 · answered by surfergrrl101 3 · 0 4

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