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a) primary haloalkanes give nucleophilic substitution via SN2 mechanism.
b) Tertiary haloalkanes give nucleophilic substitution via SN1 mechanism.
c) The rate of SN1 reactions depends only on the concentration of the nucleophile.
d) SN1 reaction is not stereospecific and if the starting material is a chiral compound the product is a racemic due to the planarity of th carbocation intermediate.
e) SN1 reactions are stereospecific with inversion of configuration.

2007-12-29 02:30:02 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

i think D

A, B, are definitely right .

E: Sn1 is inverted configuration and retent also

D. because the intermediate carbocation is planar, the central carbon is not a stereocenter. Even if it were a stereocenter prior to becoming a carbocation, the original configuration at that atom is lost. Rather, the central carbon can be prochiral. Nucleophilic attack can occur from either side of the plane, so the product might consist of a mixture of two stereoisomers


sorry for posting the wrong answer for you, i think the answer is C , i will agree with someone's answer below.
because rate of SN1 rxn is proportional to concentration of alkylhalode but not the concentration of nucleophile
i thought that is Sn2 rxn cuz rate of SN2 will depend on reactant including alkyl halide and nucleophile

answer is C
one more time , i am so sorry to give you a wrong answer.

2007-12-29 02:58:57 · answer #1 · answered by Helper 6 · 0 0

I disagree with the previous answer.

Think about the rate limiting step in SN1, and what concentrations it will depend on.

(d) is exactly true, except in special situations. The intermediate carbocation has sp2 hybridisation at the carbon atom, which is therefore flat and loses any stereochemical information at this atom in the starting material.

2007-12-29 04:02:15 · answer #2 · answered by Facts Matter 7 · 0 0

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2016-04-02 00:02:44 · answer #3 · answered by Anonymous · 0 0

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