C(x) =0.2x +30,000.
now you wrote C(80,000) which makes x= 80,000
now that you have that you plug this into the equation as fllows:
C(80,000)= 0.2(80,000) + 30,000
C(80,000)= 16,000 +30,000
C(80,000) = 46,000
2007-12-28 22:44:19
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answer #1
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answered by roxane33 4
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Understand that C is a function of x. That means "the total cost to produce jars" changes as the "number of jars" change. When 80,000 is put in place of 'x' in C(x), it means that x = 80,000
So, we simply put this value of 'x' in the expression for C(x). This would give:
C(80,000) = 0.2*80,000 + 30,000
Understand that C(40) would be 0.2*40 + 30,000
Similarly, any other value of 'x' in C(x) would change the total cost appropriately.
2007-12-29 06:39:23
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answer #2
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answered by clumsy cuz m fallin' in... 2
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Oh c'mon! Your algebra homework is only two steps! You'd get faster results using a calculator. Multiply 80,000 by 0.2 and then add that answer to 30,000.
then take your happy hand and write C(80000) = answer
2007-12-29 06:36:04
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answer #3
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answered by KeriAnnie 3
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You just plug 80,000 into anywhere there is an "x".
C(80,000) = 0.2 (80,000) + 30,000
C(80,000) = 16,000 + 30,000
C(80,000) = 46,000
Use a calculator to double check the math.
2007-12-29 06:39:18
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answer #4
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answered by Cookie 2
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Simply sub in 80,000 into the equation
0.2(80000) + 30000 = 46000
2007-12-29 06:36:15
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answer #5
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answered by Anonymous
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i allready told you it is zero what part of that do you not understand? you keep coming up with the same crap.if you don't like texas ins. call them but in the meantime stop showinig your ignorance
2007-12-29 06:40:05
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answer #6
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answered by cookie 4
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46000 ( without calculator )
2007-12-29 06:44:24
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answer #7
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answered by gjmb1960 7
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