java program that compute the series-a)1/1+1/2+1/3.......1/n. b)1/1+1/2^2+....+1/2^n?

Answer 1

Well, you could just crank it out by brute force...

double result1 = 0;
double result2 = 0;
for(double x = 1; x <= n; x+=1){
  result1 += 1.0/x;
  result2 += 1.0 / ( x*x);
}

Answer 2

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Answer 3

a)
double result = 0;
result += 1.0/((x*(x+1))/2);

b)
double result = 0;
for(double x = 1; x <= n; x+=1)
{
result += 1.0 / ( 2^x);
}