Simply because gravitational force of Moon on the raindrop is much, much weaker thän gravitational force of earth on the drop. So the drop simply follows the main force and that points to earth.
Now we come on the dance of earth and moon and the tides. Hold the hands of a friend and swirl around each other as if dancing fast. It is _not_ that you rotate around your friend or your friend around you. Instead both of you rotate around a point between you. If you weigh more or less the same this point is where your hands are. If you asked something bigger or smaller than you, then the point is more at the side of the person weighing more. Ask your friend and a girl with long hair to do the same. What does the hair of the do? It raises and starts to point away from her head. This is the so called centrifugal force.
Earth and moon do the same kind of dance. There "hands" and arms are "gravitation". On the side towards the moon the thing is clear I guess: stronger gravitation by moon, so everything is pulled a bit - and just a bit - towards moon. So we have tidal wave number 1.
What about number 2? Do you remember the hair of the dancing girl? With earth we have the same effect: the side opposite to the moon feels a centrifugal force dragging everything a bit - and just a bit - away from earth. And this creates the second tidal wave.
So we have wave number 1 due to gravitation of the moon and wave number 2 due to centrifugal force of earth and moon moving around a common center of rotation.
Annotation: because earth is so much heavier than moon, the center of this dance lies within earth itself, but it is _not_ the center of the planet.
And if you still do not understand but feel bothered by this problem, I have an idea for a science school project creating 2 different tidal waves yourself by using a wide glassbowl half filled with water, inclining the bowl a bit and then swinging it around horizontally with a rate that would balance incline and centrifugal force just at the center of the bowl, so that the side towards the axis of rotation would feel higher gravitation, the side opposite higher centrifugal force. I did not calculate it yet, but it could work. me seems.
2007-12-28 22:02:42
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answer #1
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answered by map 3
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you're the two incorrect. The moon isn't pulling the Earth everywhere, and the Earth isn't being pulled into outer area. The moon's gravity motives tides on earth, and those tides reason friction between the sea and the seafloor. And this friction is extremely gradually slowing the Earth's rotation (via some seconds a century). The regulation of conservation of momentum states that the entire momentum of a device (the rotation of the Earth and the moon and the orbits of the two products around the centre of gravity) has to stay the comparable. So if the Earth is slowing down, then some thing has to alter to shelter momentum. that must be the moon dashing up (which it can not do) or the moon shifting farther from the Earth (which it may do, and is doing). The Earth/Moon device is held in orbit via the solar's gravity, and the only way the Earth must be pulled into outer area grow to be via yet another great merchandise's gravity (and there is no great merchandise everywhere close to via to tug the Earth everywhere). The moon rather does not have the mass or gravity to tug the Earth everywhere (its the Earth that retains the moon in orbit).
2016-11-26 00:33:19
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answer #2
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answered by ? 4
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First, because the moon revolves ca. 13 degrees eastward
per day around earth, there are two tides in 23 hours, 9 minutes. Now think of the earth as covered by a continuous sphere of water. Now as far as the moon, the force of attraction averages 4 thousandths of a gal, compared to
980 gal geocentric attraction. Still, lunar attraction is subject to 1/ r^2 law. Let earth's radius be a, Moon's distance be D.
Then twice a day a point on the ocean radial to the two centers in the EM meridian is
D+a and D-a miles to the Moon, respectively repelled (high tide) by the diminished attraction and raised (high tide again) by the enhanced attraction. Ebb tide is when the point on the ocean is at D miles to the moon, or on the tangent line sqrt(D^2 + a^2)
2007-12-29 05:06:16
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answer #3
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answered by Anonymous
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Gravitational attraction is partly due to mass. The sea is a lot bigger than a raindrop (the sea is a lot bigger than you, which is one of the reasons you don't fly off into space once a month...)
The tide one is complicated - check this out...
http://www.pol.ac.uk/home/insight/tidefaq.html
2007-12-28 22:01:32
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answer #4
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answered by attakkdog 5
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