Slope equations?

Question

1a) Put this equation in mx+b form: 3y=x-15

1b)write the equation of a line this is parallel to the given line.

Answer 1

3y=x-15
y = (x- 15) /3
y = x/3 - 5

So if y = mx + b then
m = 1/3 (slope)
b = -5 (intercept with OY-axis)

b)
Any parallel line to y = x/3 - 5 has the form:
y = x/3 + b
So a parallel line has the SAME slope m =1/3.
Examples:
y = x/3 + 20
y = x/3 - 43
...
...

Bye and good luck !!

Answer 2

y=mx+b form is the slope equation
So 3y=x-15, moving the 3 to the other side, becomes
y=(x-15)/3
y=(1/3)x -5

The slope, m, is 1/3
Therefore, another line parallel to this could be y=(1/3)x-6. Basically any line works as long as the slope (m) is the same, in this case, 1/3.

Answer 3

If you ever have something on the "y" side, divide to get y by itself because {y=mx+b}.

Therefore 3y=x-15 equals y=1/3x-5. (1a)

A parellel line has the same slope, your slope is the number and x {in this case 1/3x}.

Therefore y=1/3x +/- n, where n equals any reasonable number, and you can choose negative or positive, it doesn't matter, it won't affect the parallel-ness of your equation. Why? Because it is where your starting "y intercpet" point is.

HOPE THAT HELPS!

Answer 4

1a) 3y = x -15

divide both side equation by 3

y = x/3 -5 ; m = 1/3, b = -5

1b) equation of parallel line ( it has same slope, m = 1/3)

we have to solve for b ( y-intercept) where x =0, then susbtitute in the given equation of parallel line.

y = 1/3 (x) + b ; when x = 0

y =0 + b

y = b; So your 2nd problem lacks one condition to be able to form the equation.

Answer 5

1 a) y=x/3-5 (Divide both side by 3)
1 b) y=x/3 (Both slopes that are parallel are congruent.)

Answer 6

3y/3 = (x - 15)/3

y = x/3 - 5

Answer 7

1a)y=1/3x - 5

1b) same as a 1/3x