most likely.
2007-12-28 11:58:06
·
answer #1
·
answered by Anonymous
·
0⤊
1⤋
I think so. But Zoey 101 is such a successful show, that I think that she'll probably just have a leave for a while, and come back.
2007-12-28 20:04:03
·
answer #2
·
answered by Lolaaaa! 3
·
0⤊
1⤋
Not sure what she's said on that subject, but you know teenagers have difficulting thinking about anything that far in the future.
Which is one of the reasons they should avoid having children, if they can.
2007-12-28 20:13:15
·
answer #3
·
answered by Beckee 7
·
1⤊
0⤋
After? she will probably be gone long before the baby is born
2007-12-28 19:58:53
·
answer #4
·
answered by Dean C 6
·
4⤊
0⤋
they already kicked her out she is not allowed to keep going with it and now they are talking about taking her show of the air after the newest episodes are shown.
2007-12-28 20:41:56
·
answer #5
·
answered by kate86 3
·
1⤊
0⤋
i don't know! i saw a commercial on nickelodeon that was like "goodbye zoey?" and zoey was going to england or something. so yeah i think she is leaving. it's too bad because that show wasn't that bad.
2007-12-28 19:59:50
·
answer #6
·
answered by The Big Cheese 3
·
0⤊
2⤋
they filmed the last of the show so it is over so yes she is and she is going to raise the baby in a small town
2007-12-29 11:48:43
·
answer #7
·
answered by haheha! 3
·
0⤊
1⤋
I have a feeling the producers will be somewhat involved in that decision.
2007-12-28 20:00:57
·
answer #8
·
answered by Greg 7
·
2⤊
0⤋
She could put then how is she going to support the baby i mean she could go to her family, but they already filmed the whole nexy season anyway.
2007-12-28 19:59:33
·
answer #9
·
answered by jrdw 1
·
0⤊
1⤋
I dont think it will be her decision because Nickelodeon will cut her show. Shes no role model!!!
2007-12-28 20:00:02
·
answer #10
·
answered by Anonymous
·
4⤊
0⤋
Yeah, because they're doing this new episode where she leaves campus. I hope I helped!
Great question!
I gave you a star! :) â¥
xoxo
Anne
2007-12-28 19:59:03
·
answer #11
·
answered by iheart_you_too2 3
·
1⤊
1⤋