is there a place that will tell me how to solve probs like...?

Question

4x3(2x2-x+7)?? i have to multiply it and i have no idea how

oh by the way x is actualy the letter x, not multiply

hello, its vacation, duh!

and its not in the math book and i cant ask a teacher im on vacation!!!

Answer 1

This is your question:
4x^3(2x² - x + 7)

Imagine it was:
a(b - c + d)

You would distribute the a through the parentheses to get:
ab - ac + ad

You do the same thing with your expression:
4x^3(2x² - x + 7)

(4x^3 * 2x²) - (4x^3 * x) + (4x^3 * 7)

When multiplying numbers with the same base (e.g. x^3 and x², you add the exponents). Use this rule when simplifying:
8x^5 - 4x^4 + 28x^3

Answer 2

4x3(2x2-x+7)
12(2x2-x+7) Multiply 4 and 3
12(4-x+7) Multiply2 and 2
12(11-x) Add 4 and 7
132(-x) Multiply 12 and 11
-132x Multiply 132 and -x

Check the Internet

Answer 3

Actually there are two x's in your equation. But, here goes anyway:
4x3 (2x2-x+7)=,
12 (4-x+7)=,
12(11-x)=,
132-12x
Once the value of the remaining "x" is discovered you should be able to figure the final value.

Answer 4

It has been years since I did any math but I think.....
4x3(2x2-x+7)
4x3(4-7x)
4x3(-3x)
12(-3x)
-36x

I hope that is right

Try the sites I found on the internet

Answer 5

A Math Book

Answer 6

Umm, you should probably learn in school.
That would be the best way! =D

Ask your teacher =]

Hope this helps!
Happy Holidays!

JJC

Answer 7

well, its called school, 2 120x is my guess. 2 u can go to 2 tutoring and they'll help u. k hope it helps.

Answer 8

take a look around sherlock...you ON ONE!

wtf

Answer 9

go to a teacher and ask duh