secx-cosx=sinxtanx
I know basically what to do, but I can't ever get secx-cosx to become equal to sinxtanx, or the other way around. Help??
2007-12-28 09:24:09 · 6 answers · asked by em.four 2 in Science & Mathematics ➔ Mathematics
LHS
(1 / cos x) - cos x
(1 - cos²x) / cos x
sin ² x / cos x
(sin x / cos x) (sin x)
tan x sin x
RHS
tan x sin x
LHS = RHS
2007-12-30 07:00:40 · answer #1 · answered by Como 7 · 0⤊ 0⤋
secx - cosx
= 1/cosx - cosx
= ( 1 - cos^2(x) ) / cosx
= sin^2(x) / cosx
= sinx*sinx/cosx
= sinx*tanx
2007-12-28 18:06:03 · answer #2 · answered by fraukka 3 · 0⤊ 0⤋
secx - cosx = sinxtanx
1/cosx - cosx
1/cosx - cosxcosx/cosx
1/cosx - cos^2/cosx
(1 - cos^2x)/cosx
sin^2x/cosx
sinx(sinx/cosx)
sinxtanx
2007-12-28 17:30:45 · answer #3 · answered by kindricko 7 · 0⤊ 0⤋
secx-cosx = sinxtanx
secx-cosx = 1/cosx -cosx = (1-(cosx)^2)/cosx
=(sin(x))^2/cosx = (sinx/cosx)sinx= tanx sinx
2007-12-28 17:29:03 · answer #4 · answered by Any day 6 · 0⤊ 0⤋
1/cosx - cosx = (1-cos^2x)/cosx
=sin^2x/cosx
=sinx sinx/cosx
=sinx tanx
= rhs
2007-12-28 17:29:06 · answer #5 · answered by norman 7 · 0⤊ 0⤋
1/cos x - cos x = sinx(sinx/cosx)
(1-cos^2 x)/cos x = sin^2 x /cos x
sin ^2/cos x = sin^2/cos x
2007-12-28 17:36:51 · answer #6 · answered by jamesyoy02 6 · 0⤊ 0⤋