Seal wiskers and Genetics?

Question

If you remember me again, I have another question about genetics.
I think that a cross of the two homozygous long-whiskered seals's offspring will have no short-whiskers (which is 0%) because in a punnet square it would look like this:

W W
W WW WW

W WW WW

Then I think the cross between the two heterzygous seals punnet square would look like this. I dont know what the percentge is.
Please correct me if ANYTHING is wrong.

W w
W WW Ww
w Ww ww

This is the question.
Let's say that in seals, the gene for the length of the whiskers has two alleles. The dominant allele (W) codes for long whiskers & the recessive allele (w) codes for short whiskers. What percentage of offspring would be expected to have short whiskers from the cross of two long-whiskered seals, one that is homozygous dominant and one that is heterozygous? Explain your answer and use a punnett square.

Answer 1

None of them will have short whiskers:

W W
W WW WW
w Ww Ww

You would have to have an offspring that is homozygous recessive (ww), which you cannot get from this cross, to get offspring with short whiskers.

Answer 2

Your crosses are correct for homozygous dominant x homozygous dominant (F1 is all WW, 100% long-whiskered) and also correct for heterozygous x heterozygous (F1 is 1WW: 2 Ww: 1 ww, which is 3 long-whiskered: 1 short-whiskered. It's 75% long and 25% short).

However, and this is a BIG however:
The question says that you are supposed to cross a homozygous dominant with a heterozygous.

P: WW x Ww
F1 on the Punnett square will be WW Ww on the first row, and WW Ww on the second row.
so the F1 are 1WW: 1Ww. Their phenotype ratio is all long-whiskered, or 100% long-whiskered.

Answer 3

ok so suppose the allele don't influence the phenotype in different procentage it goes like this:
P: WW x Ww
F1:you'll get 100% long whiskers
F2: you'll get either 50% short/50% long either another row of 100% long