I will just do it a little differently.
Write three consecutive numbers who's sum is 60:
x + (x-1) + (x-2) = 60
3x - 3 = 60
3x = 63
x = 21
So,
x - 1 = 20
x - 2 = 19
So the numbers are 19, 20, 21.
Note the answer is the same if we start with
x, x+1, x+2 or
x-1, x, x+1
2007-12-28 08:24:11
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answer #1
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answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6
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lets call the three numbers x y and z. since they are consecutive,
x+1=y
y+1=z
from the first equation, we know y-x+1. thus, z=(x+1)+1=x+2.
we also know that x+y+z=60.
since y=x+1, then x+(x+1)+z=60
since z=x+2, then x+(x+1)+(x+2)=60
x+x+1+x+2=60
3x+3=60
3x=60-3=57
3x=57
x=57/3=19
thus, the value of y, which is x+1, is 19+1=20. the value of z is y+1, so 20+1=z, z=21.
the three numbers are 19,20, and 21.
2007-12-28 16:42:18
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answer #2
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answered by Harris 6
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let
x = first consecutive number
x + 1 = second consecutive number
x + 2 = Third consecutive number
60 = the sum
The equation
x + x + 1 + x + 2 = 60
3x + 3 = 60
Transpose 3
3x + 3 - 3 = 60 - 3
Collect like terms
3x = 57
Divide both sides of the equation by 3
3x / 3 = 57 / 3
x = 57/3
x = 19
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The first consecutive numer is 19
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The second consecutive number is:
x + 1
19 + 1 = 20
The second consecutive number is 20
- - - - - - --
The third consecutive number is:
x + 2
19 + 2 = 21
The thire consecutive number is 21
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The Sum
19 + 20 + 21 = 60
- - - - - - -s-
2007-12-28 16:32:55
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answer #3
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answered by SAMUEL D 7
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This is a really simple problem. What part of it are you having trouble with?
Let the three numbers be x, y and z.
x + y + z = 60
We know that y = x + 1, and z = x + 2. Substituting:
x + (x+1) + (x+2) = 60
3x + 3 = 60
3x = 57
x = 19
y = 20, z = 21
2007-12-28 16:25:41
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answer #4
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answered by laurahal42 6
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OK
x + x+1 + x+2 = 60
3x + 3 = 60
3x + 57
x = 19
So the three consecutive numbers are: 19,20,21
Hope that helps.
2007-12-28 16:36:00
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answer #5
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answered by pyz01 7
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3 consecutive numbers whose sum is 3n = 60 are
n--1, n, n+1 given by 60/3 -- 1, 60/3, 60/3 +1 or 19, 20, 21.
2007-12-28 16:44:57
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answer #6
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answered by sv 7
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three consecutive numbers are
x
x+1
x+2
so the sum therefore...
x + (x+1) + (x +2) = 60
3x + 3 = 60
3x = 57
x = 19
so the three consecutive numbers are
19, 20 and 21
2007-12-28 16:24:10
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answer #7
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answered by theanswerman 3
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x+(x+1)+(x+2)=60
3x+3 = 60
3x = 57
x=19
x+1 = 20
x+2=21
2007-12-28 16:22:51
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answer #8
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answered by Anonymous
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x + (x + 1) + (x + 2) = 60
3x + 3 = 60
3x = 57
x = 19
Numbers are 19 , 20 , 21
2007-12-28 17:49:31
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answer #9
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answered by Como 7
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lower number
middle number= lower number +1 (because it has to be one more because they are consecutive)
upper number=middle number +1.
lower number + middle number + upper number=60
Substitute for the middle number and upper number with the expressions mentioned up above
lower number + (lower number +1) + (middle number +1)=60
Substitute again for the middle number:
lower number + lower number +1 + (lower number +1) +1=60.
Condense.
3 lower number + 3 = 60
Subtract 3 from both sides.
3 lower number = 57
Divide 3 from both sides
lower number =19
middle number =lower number +1 =19 +1 =20
upper number = middle number +1 =20 +1 =21
2007-12-28 16:44:03
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answer #10
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answered by Anonymous
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