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10 answers

I will just do it a little differently.
Write three consecutive numbers who's sum is 60:

x + (x-1) + (x-2) = 60
3x - 3 = 60
3x = 63
x = 21
So,
x - 1 = 20
x - 2 = 19

So the numbers are 19, 20, 21.

Note the answer is the same if we start with
x, x+1, x+2 or
x-1, x, x+1

2007-12-28 08:24:11 · answer #1 · answered by 1,1,2,3,3,4, 5,5,6,6,6, 8,8,8,10 6 · 0 1

lets call the three numbers x y and z. since they are consecutive,
x+1=y
y+1=z
from the first equation, we know y-x+1. thus, z=(x+1)+1=x+2.
we also know that x+y+z=60.
since y=x+1, then x+(x+1)+z=60
since z=x+2, then x+(x+1)+(x+2)=60
x+x+1+x+2=60
3x+3=60
3x=60-3=57
3x=57
x=57/3=19
thus, the value of y, which is x+1, is 19+1=20. the value of z is y+1, so 20+1=z, z=21.
the three numbers are 19,20, and 21.

2007-12-28 16:42:18 · answer #2 · answered by Harris 6 · 0 0

let

x = first consecutive number

x + 1 = second consecutive number

x + 2 = Third consecutive number

60 = the sum

The equation

x + x + 1 + x + 2 = 60

3x + 3 = 60

Transpose 3

3x + 3 - 3 = 60 - 3

Collect like terms

3x = 57

Divide both sides of the equation by 3

3x / 3 = 57 / 3

x = 57/3

x = 19
- - - - - - - -

The first consecutive numer is 19

- - - - - - - -

The second consecutive number is:

x + 1

19 + 1 = 20

The second consecutive number is 20

- - - - - - --

The third consecutive number is:

x + 2

19 + 2 = 21

The thire consecutive number is 21
- - - - - - - - - -

The Sum

19 + 20 + 21 = 60

- - - - - - -s-

2007-12-28 16:32:55 · answer #3 · answered by SAMUEL D 7 · 2 0

This is a really simple problem. What part of it are you having trouble with?

Let the three numbers be x, y and z.

x + y + z = 60

We know that y = x + 1, and z = x + 2. Substituting:

x + (x+1) + (x+2) = 60
3x + 3 = 60
3x = 57
x = 19

y = 20, z = 21

2007-12-28 16:25:41 · answer #4 · answered by laurahal42 6 · 0 0

OK

x + x+1 + x+2 = 60
3x + 3 = 60
3x + 57
x = 19

So the three consecutive numbers are: 19,20,21

Hope that helps.

2007-12-28 16:36:00 · answer #5 · answered by pyz01 7 · 0 0

3 consecutive numbers whose sum is 3n = 60 are
n--1, n, n+1 given by 60/3 -- 1, 60/3, 60/3 +1 or 19, 20, 21.

2007-12-28 16:44:57 · answer #6 · answered by sv 7 · 0 0

three consecutive numbers are
x
x+1
x+2
so the sum therefore...
x + (x+1) + (x +2) = 60
3x + 3 = 60
3x = 57
x = 19
so the three consecutive numbers are
19, 20 and 21

2007-12-28 16:24:10 · answer #7 · answered by theanswerman 3 · 0 0

x+(x+1)+(x+2)=60

3x+3 = 60

3x = 57

x=19
x+1 = 20
x+2=21

2007-12-28 16:22:51 · answer #8 · answered by Anonymous · 1 0

x + (x + 1) + (x + 2) = 60
3x + 3 = 60
3x = 57
x = 19
Numbers are 19 , 20 , 21

2007-12-28 17:49:31 · answer #9 · answered by Como 7 · 3 0

lower number
middle number= lower number +1 (because it has to be one more because they are consecutive)
upper number=middle number +1.

lower number + middle number + upper number=60

Substitute for the middle number and upper number with the expressions mentioned up above

lower number + (lower number +1) + (middle number +1)=60

Substitute again for the middle number:

lower number + lower number +1 + (lower number +1) +1=60.

Condense.

3 lower number + 3 = 60

Subtract 3 from both sides.

3 lower number = 57

Divide 3 from both sides

lower number =19

middle number =lower number +1 =19 +1 =20

upper number = middle number +1 =20 +1 =21

2007-12-28 16:44:03 · answer #10 · answered by Anonymous · 0 0

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