If x=y^3 - 80, what is the value of y in terms of x?

Answer 1

y ³ = x + 80
y = (x + 80)^( ⅓ )

Answer 2

first rearrange the question in terms of y, so we have
y^3=x+80

because y is to the power of three, we need to raise x+80 to the power 1/3 to get the value of 1 y, so we get
y=(x+80)^(1/3)

Hope this helps!!!

Answer 3

x=y^3-80
u need y in terms of x. so, our goal is to isolate the y by doing the inverse operations.
x=y^3-80
since u subtracted 80, u must now add 80 on each side.
x+80=y^3-80+80
x+80=y^3
now, since u cubed y, we must do the inverse, cube root on each side.
cube root of (x+80)=cube root of (y^3)
cube root of (x+80)=y
y=cube root of (x+80)

Answer 4

rewrite as

y^3 = x + 80
and solve for y
y = (x + 80)^(1/3)

Answer 5

x=y^3-80
80=y^3
cuberoot(80)=y

Answer 6

x=y^3-80
y=cubrt(x+80)ANS

Answer 7

well if x
isnt a number then
why could mean anything but in
my turms the answer would be 22