find i, where -3000*(1+i)^(101/365)=1967.26*(1+i)^(106/365)?

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find i, where -3000(1+i)^(101/365)=1967.26(1+i)^(106/365)?

2007-12-28 07:45:35 · 2 answers · asked by nc 3 in Science & Mathematics ➔ Mathematics

You need to use De Moivre's formula. Pleas visit:
http://en.wikipedia.org/wiki/De_Moivre's_formula

2007-12-28 07:49:30 · answer #1 · answered by Dragon Boy 1 · 0⤊ 1⤋

-3000*(1+i)^(101/365)=1967.26*(1+i)^(106/365)
-3000 = 1967.26*(1+i)^(1/73)
-3000/1967.26 = (1+i)^(1/73)
2.3875 X 10^13 = 1+i
i = 2.3875 X 10^13 - 1

2007-12-28 16:34:49 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋