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Can you tell me if these are linear equations or not and plz tell me why they are or why they aren't linear equations

1. 5y+2y=7 3. 3/5x-2/3y=5
4. y/3=3.

2. y+1/x=7

2007-12-28 06:10:58 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

linear equations are those that form a straight line graph
it's basic formula is ax +by=c. Focus on the x and y.

1. linear
2. nope
3. yeah
4. yuppa

2007-12-28 06:15:52 · answer #1 · answered by Anonymous · 0 0

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RE:
How can you tell if a certain equation is a linear equation or not??
Can you tell me if these are linear equations or not and plz tell me why they are or why they aren't linear equations

1. 5y+2y=7 3. 3/5x-2/3y=5
4. y/3=3.

2. y+1/x=7

2015-08-18 21:11:21 · answer #2 · answered by ? 1 · 0 0

linear equation is one in which any variable term is of degree 1

1. simplifies to 7y = 7 or y = 1, the power of y is 1
yes, it is linear

2. y + 1/x = 7 to clear the fraction, multiply by x
yx + 1 = 7x the yx term is degree 2 (sum of their powers)
not linear

3. 3/5x - 2/3y = 5 If the x and y are in the denominators then this is not linear since to get them out of the denominators you would multiply by xy--this will create a 5xy on the right side which is degree 2 again.

If the x and y are just next to the fractions, then it is linear as each is of degree 1

4. y/3 = 3
simplifies to y = 9
linear (degree 1 on y)

2007-12-28 06:28:03 · answer #3 · answered by Linda K 5 · 0 0

A linear equation of two variables is of the form
ax + by + c = 0, a^2 + b^2 ≠ 0.
2 and 3 are not linear equations as they are not of the above form.

2007-12-28 06:17:29 · answer #4 · answered by Madhukar 7 · 0 0

Linear equations
1. Is a linear equation because x and y have degree 1
2. Not a linear equation because x has degree -1
3. Not linear because x and y have degree -1
4. Linear because y has degree 1

2007-12-28 06:15:48 · answer #5 · answered by digit 1 · 0 2

1. this simplifies to y=1, which is linear because the variable is to the first power.

2. since x is to the negative first power, this is not linear.

3. if (3/5) and (2/3) are coefficients, then this is linear. If one is a coefficient and one has a variable in the bottom, then it isn't. However, if both have variables in the bottom, then it's linear because you can divide 1 by the whole equation.

4. simplifies to y=9. definitely linear.

2007-12-28 06:18:48 · answer #6 · answered by my_chiclet 2 · 0 0

In linear equations, the unknown(s) is raised only to power 1, e.g., no power. Also, linear equations can be simplified to an equality of he type "polynomial of degree 1 equals constant".

In your examples, 1. and 4. are obviously linear. 2. isn't linear: 1/x = x^-1.

4. If you meant (3/5x) - (2/3y) = 5, it isn't linear. If you meant (3/5)x - (2/3)y = 5, it is linear.

2007-12-28 06:41:22 · answer #7 · answered by jcastro 6 · 0 0

A linear equation must be a weighted sum of its parts. The easiest way to check is to see if all variables are all to the first power and if none of the variables are multiplied to each other. It is ok if they are multiplied by constants.

1. linear
2. nonlinear, since x is raised to the -1 power
3. linear
4. linear

2007-12-28 06:18:00 · answer #8 · answered by b1gmuff 3 · 1 0

To begin, both x and y should be to the first power (in other words, not have any exponents, such as x²) in order for the equation to be considered linear. One way to express a linear equation is simply " y = ax+b ", also known as slope-intercept form, where "a" is the slope of the line, and "b", being the constant term, is the y-intercept. For your equation, y = 2x + 12, a=2, and 12=b.

2016-03-18 00:49:09 · answer #9 · answered by ? 3 · 0 0

a linear equation has two or less variables and none of the variables are raised to a power.

1) is linear, its a special case y is a constant so its a horizontal line

2) is a linear two variables and both are not raised to a power.

3) is a linear two variables and both are not raised to a power.

4) is linear, its a special case y is a constant so its a horizontal line

2007-12-28 06:14:20 · answer #10 · answered by Brian K² 6 · 2 2

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