I NEED TO SOLVE THIS AND FIND THE CENTER AND RADIUS OF THE CIRCLE. Please show me the steps / answer and you'll get best answer :) PLEASE HELP
(x-4)^2 + (y+3)^2 = 16
2007-12-28 05:58:00 · 3 answers · asked by Jaz 'ma' Taz 2 in Science & Mathematics ➔ Mathematics
the center is (4,-3) and the radius is 4
- first (x-4) u take the opposite sign and you get 4 for the x axis
- then (y+3) u take the opposite sign and you get -3 for the y axis
- then u take the square root of 16 which is 4 and thats the radius
hope that helps
2007-12-28 06:30:10 · answer #1 · answered by Anonymous · 0⤊ 0⤋
it's simple. remember: (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius. So in your equation, 4 is the h and -3 is the k which means that (4,-3) is the center of the circle. Then 16 is your r^2 which means that 4 is your radius. :D
2007-12-28 14:03:48 · answer #2 · answered by Anonymous · 0⤊ 0⤋
(x-h)^2 + (y-k)^2 = r^2 is the equation of a circle with center at (h.k and radius = r.
So your answer is center = (4,-3) and radius = 4
2007-12-28 14:03:39 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋