2007-12-26 22:48:00 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
tanxcosx + cotxsinx
= (sinx/cosx)cosx + (cosx/sinx)sinx
= sinx + cosx
.,.,.,.,
2007-12-26 23:10:12 · answer #1 · answered by The Wolf 6 · 2⤊ 3⤋
Dear Mr. mk:
Using the trigonometric identities we discover that of the
following:
tan x cos x + cot x sin x = ( sin x / cos x ) * ( cos x ) +
( cos x/ sin x ) * ( sin x )
tan x cos x + cot x sin x = sin x + cos x
Sincerely:
willard_thomas_jr@yahoo.com
(a.k.a. - calvaliear )
2007-12-29 14:10:46 · answer #2 · answered by calvaliear 5 · 0⤊ 1⤋
Prove that: sin x + cos x = tan xcosx + cotxsinx
sin x + cos x = (sin x/cos x)(cos x) + (cos x/sin x)(sin x)
sin x + cos x = sinx + cosx ANS
teddy boy
2007-12-27 08:55:38 · answer #3 · answered by teddy boy 6 · 0⤊ 3⤋
we know that tanx = sinx/ cosx and cot x = cos x/ sin x
hence if we take RHS
tan x cos x + cot x sin x
= (sin x / cos x) cos x + (cos x / sin x) sin x
= sin x + cos x
= LHS
2007-12-27 07:57:15 · answer #4 · answered by KJ_Jockey 2 · 0⤊ 3⤋
= tan xcos x + cot xsin x
= (sinx/cosx)cosx + (cosx/sinx)sinx defn of tanx and cot x
= sinx + cosx cross cancel
2007-12-27 07:07:20 · answer #5 · answered by saejin 4 · 0⤊ 3⤋
well since tan =sin/cos we have sin =tancos and cot=1/tan
tancos+tancos/tan=tancos+cos =sincos/cos+cos= sin +cos
2007-12-27 06:53:06 · answer #6 · answered by Happy-Miserable-Female 3 · 0⤊ 3⤋
tan x cos x + cot x sin x
= (sin x / cos x) cos x + (cos x / sin x) sin x
= (sin x cos x) / cos x + (cos x sin x) / sin x
= sin x + cos x
2007-12-27 07:05:09 · answer #7 · answered by Raichu 6 · 2⤊ 2⤋
RHS
(sin x / cos x) cos x + (cos x / sin x) sin x
sin x + cos x
LHS
sin x + cos x
LHS = RHS
2007-12-27 08:10:19 · answer #8 · answered by Como 7 · 2⤊ 3⤋