can someone help me with this math problem plz? plz show work.it deals with triangles and medians.?

Question

In triangle ABC, AB is the hypotenuse, median AD = 2008, median BE = 2007. Find x where AB = 10 sq. rt. x

Answer 1

Let the side AC be of length 2b
Let the side BC be of length 2a

By Pythagoras:
4a^2 + b^2 = 2007
a^2 + 4b^2 = 2008

By substitution:
a^2 + 4(2007-4a^2) = 2008
6020 = 15a^2
a = sqrt(6020/15)
b = sqrt(1205/3)

By Pythagoras:
4a^2 + 4b^2 = 100x

x = 32.12

Answer 2

the above answer is going about the right way except

the first two pythagorean eq should equals to 2007^2 and 2008^2