How many Cl- ions are present in 2.00 mol of KCl?

Question

Help! My teacher has never taught my class how to solve problems similar to this. Instead he gave a summative lab with very similar questions as the one show above. And sadly our textbooks do not explain how to solve such a problem very well. Texas high school textbooks suck!

I have tried everything. I have added the g/mol & amu's. I have even solved for the percentage that each element occupies in the problem---as so far I have been unsuccessful. Can someone please tell me how to solve this problem?

Here's the question:

1)How many Cl- ions are present in 2.00 mol of KCl?

[A] 12.04 * 10^23
[B] 6.02 * 10^24
[C] 2.00
[D] 0.5

A link or diagram would be very appreciated.

Answer 1

KCl breaks up into K+ ions and Cl- ions.

So, if you have 2.00 mol of KCl, you will have 2.00 mol of Cl- ions.

Remember that 1 mol = 6.02x10^23 representative particles.

So, 2.00 mol Cl- ions = 1.20x10^24 Cl- ions