The sum of 4 consecutive intergers is 90 . what are the numbers?

Question

please explain in detail...thank you

Thanks all you guys are super smart. All of your answers realy help me to understand the concept..maybe I might get an A on my next test.

Answer 1

Four consecutive integers are represented by:
x, x+1, x+2, x+3

Their sum is 4x+6

4x+6 = 90

subtract 6 from both sides:

4x = 84

divide both sides by 4:
x = 21

The 4 integers are: 21, 22, 23, 24

that's it! :)

Answer 2

in case you will possibly choose for to renowned the thank you to sparkling up this algebraically, somewhat than in basic terms having an answer... (and that i understand you probably did not ask for a technique, yet right here it quite is): you have some selection, n. The numbers that come after it (consecutive) are n + a million, n + 2, et cetera. besides, you have 4 integers in entire, and their sum is -2. (n) + (n + a million) + (n + 2) + (n + 3) = -2 4n + 6 = -2 4n = -8 n = -2 for this reason, if n = -2... First selection: n = -2 2nd selection: n + a million = -a million 0.33 selection: n + 2 = 0 Fourth selection: n + 3 = a million you have your numbers. This works for any sum, and for any volume of numbers. solid luck!

Answer 3

If n is the lowest of these integers, then the integer that comes right after is n+1, followed by n+2, then n+3. Adding up these four consecutive integers gives 90, so:
n + (n+1) + (n+2) + (n+3) = 90

Solve this for n, then use that value of n to find the other three numbers.

Answer 4

Let x = the first number
Let x+1 = the second number
Let x+2 = the third number
Let x+3 = the fourth number

Then x + (x+1) + (x+2) + (x+3) = 90

So, 4x=84; x=21
the x+1 = 22
and x+2 = 23
and x+3 = 24

Answer 5

Let x = the lowest Integer

x+(x+1)+(x+2)+(x+3)=90
4x+6=90
4x=84
x=21

The numbers are 21, 22, 23, 24

Answer 6

okay so
let x= the first number
therefore
x+1=the second number
x+2=the third number
x+3=the last number

so when you put that all together you get
x+x+1+x+2+x+3=90
add you like thems
4x+6=90

then get 4x by itself so subtract 6 from both sides and you get:
4x=84

now get x by itseld so divide 4 from both sides and you get:
x=21

so go back to the eqaution at the top
21+1=second number
21+2=third number
and 21+3= last number

so the intergers are 21,22,23,24

Answer 7

x+x+1+x+2+x+3=90

4x+6=90
4x+6-6=90-6
4x=84
x=21
x+1=22
x+2=23
x+3=24 21+22+23+24=90

Answer 8

here is a different way to compute this: the four numbers sum to 90 so their average is 22.5. You know the numbers are integers, so you need two integers larger than 22.5 and two smaller than 22.5; since they are consecutive, they must be:

23 and 22 (to average to 22.5)
24 and 21 (to average to 22.5)

and they sum to 90, so this can be done without using algebra.