A math problem?

2 ⤊

I dont understand this...

If sqrt x-a =b , x >a, which experssion is equivalent to x ?

b^2 -a

b^2+a

b-a

b+a

If you can,please explain why. Thank you.

2007-12-26 05:29:16 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

Square both sides to get

x - a = b^2

Then add a to both sides to get

x = b^2 + a

2007-12-26 05:34:37 · answer #1 · answered by jtabbsvt 5 · 0⤊ 0⤋

(x - a)^1/2 = b
x - a = bÂ²
x = bÂ² + a

2007-12-26 13:34:24 · answer #2 · answered by gebobs 6 · 1⤊ 0⤋

root(x-a) = b , then ,

x -a = b^2
x = a+b^2

2007-12-26 13:33:28 · answer #3 · answered by Nur S 4 · 1⤊ 0⤋

Sorry im in 5th Grade!!

2007-12-26 13:36:25 · answer #4 · answered by Abby 2 · 0⤊ 1⤋