mathss questions.?

Question

1. Solve 2x^2 - 3x - 1 = 0

2. express 5 - 2 ln x^3 - 2 ln y as a single logarithm.

3. simplify 2x^2 multiplied by the 5th root of x then all of that divided by x^0.

4. write down all the factors o 15 and hence factorise x^2 - 8x + 15.

Answer 1

2x^2 - 3x - 1 = 0

x = 3 +/- sqrt(9+8) / 4
x= 3 + /- sqrt(17) / 4

x = [3 + sqrt(17)]/4 or x = [3 - sqrt(17)]/4


#2) 5 - 2 lnx^3 - 2 ln y

= ln e^5 - ln x^6 - ln y^2

= ln e^5/[(x^6)(y^2)]


#3) 2x^2(x^1/5) / x^0
= 2x^(2/5)

#4) 1*15, 3*5
x^2 - 8x + 15
= (x - 3) (x - 5)

that's it! :)

Answer 2

1)
by using formula method:
[-b±√(b² - 4ac)]/2a
a=2, b= -3, c=-1
substitube a,b,c inside d formula.
= [ 3 ±√(9 +8)]/4
= [3 + √17]/4 OR [3 - √17]/4
= 1.7808 OR -0.2808

usually we are using factorisation to solve tis question,but in tis case,we can use it.. we can either use formula method or completing the square..

3)
2x²(x^1/5) / x^0
= 2x^(2/5)

4)
factor of 15 = 1,3,5,15
x ²- 8x + 15
= ( x - 3)(x - 5)

Answer 3

x = [3 +/-sqrt(18)]/(2*2)
= 3/4 +/- 3/4sqrt(2)= 3/4 (1 +/-sqrt(2))

5 - ln(x^6/y^2)

2x^2 *x^1/5 = 2x^(2/5) , since x^0 = 1

1,3,5,15
(x-3)(x-5)

Answer 4

4. 1,15,3,5,-1,-15,-3,-5
I think you are looking for the last 2

Answer 5

Are you bored buddy?