Run to park @ 6 mph, run back at 10 mph. Trip takes 1 hour how far away is park from starting point?

Answer 1

Let x be the time it takes to run to the park and (1 hour - x) be the time it takes to run back. Since the distance to and from the park are equal, then we can equate the two expressions.

Then 6x = 10(1 - x).

Manipulating the above equation, we get this:

6x = 10 - 10x
16x = 10
x = 10/16 = 5/8 hours.

Distance = Rate x Time = 6 mph. x (5/8 hrs.) = 3.75 miles

Answer 2

3 3/4

Answer 3

distance = rate X time

d = rt which means t = d/r

The time running to the park is d/6

The time running away from the park is d/10

Both times together = 1 hour so

d/6 + d/10 = 1

multiply both sides of equation by 30:

5d + 3d = 30

8d = 30

d = 3.75

Answer 4

the park is 2.25 miles away...

solution:

we know that v=s/t and s=v/t
and we know that the distance to park equals the distance from park...
we mark 'x' to be the time needed to get to the park, 1-x is then time needed to get back from park.

we can write:
6/x=10/(1-x)
from that we have that x=0.375 so the time needed to get to park is 0.375 hours.
the distance is 0.375h*6mph=2.25

alternatively we could just divide hour in 6:10 ratio (ratio of speeds) and then we would get the duration of the trip (back and forth) and we would get the same result:
(1/16)*6=0.375hour
then the distance= 0.375*6mph...= 2.25 miles...

Answer 5

it would be superb. Worst case senerio your rims will bend and the tires will deflate. in case you drove it after it would be ok tho. To be on the risk-free area you are able to take your motor vehicle to get the wheels aligned. in the event that they do no longer look to be aligned right over an prolonged quantity of time your tires won't placed on out right and you will choose tires in simple terms before customary yet no longer something too undesirable.

Answer 6

3 3/4 miles???

Answer 7

16 miles away