If I have a line that is say y=3, but the line does not run on forever, it goes from (1,3) to (7,3) how would I write the entire equation for this line?
2007-12-26 02:58:39 · 5 answers · asked by Anonymous in Education & Reference ➔ Homework Help
for the domain, would i have to do it like 3>x>7 or would i do it like {x:xER 3>x>7}
2007-12-26 03:44:07 · update #1
You should write your function this way:
y = 3, x ε (1, 7).
The above is read y = 3, where x is an element of the set from 1 to 7. You would do this because the line runs from the point where x = 1 to the point where x = 7.
2007-12-26 03:52:10 · answer #1 · answered by MathBioMajor 7 · 0⤊ 0⤋
You restrict the domain. Y=3 where 1<=x<=7 (< is above =)
Actually, your domain is backwards. X is greater than or equal to 1 and less than or equal to 7. The way you have it, you are saying X is less than 3 and greater than 7. That's impossible.
The format depends on how precise you have to be on the notation. In most math classes, the second format is not necessary.
2007-12-26 03:06:29 · answer #2 · answered by tkquestion 7 · 0⤊ 0⤋
The equation is y=3 for the horizontal line that contains line segment where 3>= x<=7
2007-12-26 03:08:58 · answer #3 · answered by Elmo 4 · 0⤊ 1⤋
get y by employing itself... circulate 2x to the different area and alter the sign to -... so which you get so a approaches: -3y = -2x +4 if 3 is the y element you go with, placed 3 in determination to 4... the slope (that's the -2x) is going to be an identical on account which you want a line parallel... so your very final answer ought to examine: -3y = -2x + 3 oops...slope intercept sort: 2x - 3y = 3 it is been a on an identical time as for me so i'm hoping it is ideal!
2016-11-25 01:29:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Y = 3 x{1,7}
2007-12-26 03:26:43 · answer #5 · answered by spirit dummy 5 · 0⤊ 1⤋
you have school after christmas?
2007-12-26 03:01:24 · answer #6 · answered by A7X Fan (RIP The Rev) 5 · 0⤊ 0⤋