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1.5 meters in 10 seconds. How much power was used to move the barbell?

2007-12-25 14:57:29 · 3 answers · asked by Anonymous in Science & Mathematics Physics

3 answers

p=Wd/t
to get Wd:
Wd=fd

p=fd/t
=98N*1.5m/10s
=147J/10s
=14.7 W

2007-12-25 15:12:58 · answer #1 · answered by Anonymous · 0 0

Power P is rate of energy flow E/t
P=E/t
Energy E is work done by force F over parallel distance s
E=F s

P= 98 x 1.5/ 10=14.7 W

2007-12-25 23:04:51 · answer #2 · answered by Edward 7 · 0 0

power = work/time.

Thus, the work equals force times distance 98 x 1.5 = 147 Nm or joules

time is 10 seconds.

its 147/10 = 14.7 J/s or 14.7 Watts.

overall,

W= Fd

Power =Work/time

2007-12-25 23:04:02 · answer #3 · answered by codebreaker1011 2 · 1 0

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