what is the acceleration of a biker who reaches a speed?

2 ⤊

of 25 m/sec in 15 seconds?

2007-12-25 14:51:16 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics

a=v/t
=25m/s/15s
=1.66m/s2

2007-12-25 15:15:43 · answer #1 · answered by Anonymous · 1⤊ 0⤋

If he starts from a state of rest then its sped V at a time t is
V=at
where from
a=V/t=25/15 m/s^2

2007-12-25 16:28:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋

a = Δv / Δt = (25 m/s) / (15 s) = 1.67 m/s^2

In other words, the average acceleration is just the change in velocity divided by the change in time.

2007-12-25 14:53:39 · answer #3 · answered by DavidK93 7 · 1⤊ 0⤋