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Well, you know the m in y=mx+b is the slope of a linear line. In order to find slope, m, we can use the formula m= y2-y1/x2-x1, where x1,x2,y1,y2 are x points and y points in a line, so we have m= 2-5/4-1 = -3/3 = -1

Plugging in the fact that m= -1 into y=mx+b, we have
y=-x+b... to solve for b, we choose a point on the line, say, (1,5), and plug it into the y=-x+b equation, so we get
5=-1+b
b=6
So our equation for the line is
y=-x+6

2007-12-25 14:54:32 · answer #1 · answered by ¿ /\/ 馬 ? 7 · 0 0

Use the slope-intercept form of a line, specifically y = mx+b where m is the slope of the line and b is the y-intercept (when x=0).

The slope between 2 points (a,b) and (c,d) is (d-b)/(c-a) which in your case is -3/-3 = 1, so m=-1.

So we have y = -x + b.

Point (1, 5) is on the line so 5 = 1 + b or b = 6.

Therefore the equation of the line is y = -x + 6

2007-12-25 14:56:59 · answer #2 · answered by MartinWeiss 6 · 0 0

The slope of the line m = (5-2)/(1-4) = -1
Find the y-intercept by solving for y in (5-y)/(1-0) = -1
5-y = -1
y = 6
Using the slope-intercept method:
y = -x +6

2007-12-25 15:31:50 · answer #3 · answered by Arnold K 2 · 0 0

the 1st 2 questions do no longer even make experience. each and every line has an limitless variety of factors. 3) to locate the Y intercept, plug in 0 for X and resolve for Y: 0-2y=40 two y=-21 to locate the X intercept, plug in 0 for y and resolve for x: 7x-0=40 two x=6 4) The slope is the improve (substitute in y) divided by employing the run (substitute in x): (2-2)/(-6-a million) = 0/-7 = 0

2016-10-19 22:23:05 · answer #4 · answered by staude 4 · 0 0

Here is the answer...

x1 = 1
y1 = 5
x2 = 4
y2 = 2



y – y1 = y2 – y1
x – x1 x2 – x1


y – 5 = 2 – 5
x – 1 4 – 1

y – 5 = (x – 1) - 1

y = -x +6

2007-12-25 16:09:38 · answer #5 · answered by Haziq 1 · 0 0

the equation is: y= -1x + 6. you find this by doing rise/run which is 5-2/4-1= -3/3=-1 is the slope. plug it in for one of the points to find the y intercept (6)

2007-12-25 14:56:16 · answer #6 · answered by Anonymous · 0 0

y=mx+b is the stndard form of a linear equation. m is the slope ((y2-y1)/(x2-x1)). the y-intercepts is b (the value of y when x=0). to solve for m, input the values of y2,y1,x2,and x1.
(2-5)/(4-1)=m
-3/3=m
m=-1
now input this into the equation.
y=(-1)x+b
or
y=b-x
solve for b by inputting any value pair.
(5)=b-(1)
5+1=b-1+1
6=b
thus,
y=6-x

2007-12-25 15:07:11 · answer #7 · answered by Harris 6 · 0 0

2 - 5 -3/3
____=
4-1

-3/3= -1 is the slope

y= -1x + b

y - 5= -1(x - 1)
y-5= -x + 1
y= -x + 6

2007-12-25 14:55:22 · answer #8 · answered by james brown 4 · 0 0

y-y = m(x-x)
y - 1 = m(x-5)

y = m(x-5) +1

m = slope = change in y / change in x

5-2 / 1-4 = 3/-3 = -1

so we have y = -(x-5) +1

you can multiply to get it into standard form

2007-12-25 14:58:48 · answer #9 · answered by P 3 · 0 0

y = m*x +b

5= m*1 +b
2= m*4 +b

m = -1, b= 6

y = -x + 5 ■

2007-12-25 15:00:57 · answer #10 · answered by ? 5 · 0 1

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