Very tough math question.?

Question

Solve for x:
(2^x) + (3^x) - (4^x) + (6^x) - (9^x) = 1

Pretty hard when x is the exponent isn't it?






This has nothing to do with the question, but can someone tell me how to get exponents easily here. I can copy-paste exponent numbers from Microsoft Word easily, but not exponent variables like x.
When I paste 2^x from Word, it looks like 2x here.
But 2² is still 2².

Jaya got it! Many of you got 0, but she showed her work.

Answer 1

taking log from both side

log a^b = bloga

so ,

xlog2 +xlog3 -xlog4 +xlog6-xlog9 = log1

x log(2*3*6/4*9) = log1

x log 1 = log 1

log 1^x = log 1

Taking antilog from both side

1^x = 1

therefore x =0

anything raise to power zero is one

now to check the answer substitute x=0 in the equation and you will get LHS = RHS

Answer 2

Actually it's quite simple, x = 0.

Making each group in the question = 1, any number raised to the zero power equals 1 so:

1 + 1 - 1 + 1 - ! = 1.

Answer 3

0

There may be more than one answer but I'm sure 0 is one of them. I don't really know how to do this mathematically, I kinda used logic and tried 0 and it worked.

Answer 4

something to do with logarithms. just remember:
log answer/ log base= exponent
i dunno how to solve the problem though. but 0 works as the value for x.

and i dont get that paste thingy either im also getting 2x. but just do 2^x it will work fine everyone knows what it is

Answer 5

I don't know how to obtain all the possible answers, but one solution that springs to mind is x=0.

Answer 6

try using logarithms, Ln

Answer 7

nice answer jaya... good job.. we have the same solution!