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if o <= x <= y and (x + y)^2 - (x-y)^2 >= 25
what is the least possible value of y ?

2007-12-25 12:45:58 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

(x+y)² - (x-y)² ≥ 25
x² + 2xy + y² - x² + 2xy - y² ≥ 25
4xy ≥ 25
y ≥ 25/(4x)
for x ≥ 0, that's the right half of a hyperbola, shaded above.
for y ≥ x ≥ 0, that's the line y = x, shaded above.
so the minimum y is the bottom of the overlapping region where y = x intersects with y = 25/(4x), so we solve
y = 25/(4y)
y² = 25/4
y = 5/2

2007-12-25 13:03:59 · answer #1 · answered by Philo 7 · 1 0

(x + y)^2 - (x-y)^2 >= 25
(x+y - x+y)(x+y + x-y) = 2y *2x >= 25
x= y=3

2007-12-25 13:02:33 · answer #2 · answered by hayk s 2 · 0 0

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