Hello ,and how would you differentiate 80/(Q+1)? Thank you....?

Answer 1

respect to Q right?

you can use quotient rule, which is:
d/dx (u/v) = (u'v - v'u)/v^2

or you can use the chain rule, which is what i prefer to use
80/(Q+1) = 80(Q+1)^-1

80 d/dQ (Q+1)^-1
let u = Q+1
then d/du (u^-1) = -u^-2
d/dQ (Q+1) = 1

80*-u^-2 * 1

recall the u = Q + 1

80 * -(Q+1)^-2 or -80/(Q+1)^2 <== answer

Answer 2

I take it that you want to differentiate with respect to Q right? If so just say this out loud..and write it down as you say it........"The derivative of the top multiplied by the bottom, minus the derivative of the bottom multiplied by the top, over the bottom squre" ...THis will apply for all probalmes where you have to divide

Answer 3

80/(Q+1) = 80(Q+1)^(-1)
use:
derivative of a ^(m) = ma^(m-1)
here m = -1;
derivative of a^(-1) = -1* a^(-1-1) = -1/a^2
Derivative of 80/(Q+1) = -80/(Q+1)^2