Helphow do I solve 4x+3-13x-7<2(3-4x)?

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Helphow do I solve 4x+3-13x-7<2(3-4x)?

2007-12-25 08:29:01 · 4 answers · asked by Luis J 1 in Science & Mathematics ➔ Mathematics

4 answers

1) combine the x's and constants and ditribute to get:
-9x-4<6-8x
2) then add 4 to both sides, and add 8x to both side to get:
-x<10
3) divide by -1 and switch the inequality sign because when you divide by a negative # you have to switch the sign and you get your answer:
x>-10

2007-12-25 08:36:24 · answer #1 · answered by Mike D 1 · 1⤊ 0⤋

4x + 3 - 13x - 7 < 2(3 - 4x)
- 9x - 4 < 6 - 8x
- 10 < x
x > - 10

2007-12-25 19:14:15 · answer #2 · answered by Jun Agruda 7 · 3⤊ 0⤋

4x+3-13x-7<2(3-4x)

4x+3-13x-7<6-8x
-9x-4<6-8x
-10>x

2007-12-25 17:44:11 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

4x+3-13x-7<2(3-4x)
-9x-4<6-8x
-10 x>-10.ANS.

2007-12-25 16:38:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋