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(4, -1), (6, -7)

a. 32
b. 32√2
c. 2√10
d. 8

2007-12-25 05:16:04 · 6 answers · asked by mommawe'regoingtohell 1 in Science & Mathematics Mathematics

6 answers

√[(x2 - x1)^2 + (y2 - y1)^2]
= √[(6 - 4)^2 + {-7 - (-1)}^2]
= √[2^2 + (-7+ 1)^2]
= √[4 + (-6)^2]
= √(4 + 36)
= √40
= 2√10

So (c) is correct.

2007-12-25 05:23:13 · answer #1 · answered by psbhowmick 6 · 1 0

Distance formula is (xv2 - xv1)^2 + (yv2 - yv1)^2 = c^2 ==> (6-4)^2 + (-7-(-1))^2 = 2^2 + (-6)^2 = 4 + 36 = 40 = c^2 ==> c = sqrt (40) = 2sqrt(10).

2007-12-25 13:49:07 · answer #2 · answered by flyfisher_20750 3 · 0 0

distance formula to find the distance between the points (a,b) and (c,d) = sqrt [(a-c)^2 +(b-d)^2]

Therefore distance formula to find the distance between the points. (4, -1)and (6, -7) is
= sqrt [(4-6)^2 +(-1+7)^2]
= sqrt [(-2)^2 +(6)^2]
= sqrt [4 +36] =sqrt [40] = 2 sqrt [10] =2 X 3.16228 =6.325

2007-12-25 13:31:20 · answer #3 · answered by Dr K.L.Verma 2 · 0 0

a^2 +B^2=C^2
(6-4)2 + (-7-(-1))2 = c^2
(2)2 + (-6)2 = c^2
4 + 36 = c^2
c^2 = 40
c^2 = 4 X 10
c = 2/10

The answer is c)

2007-12-25 13:26:31 · answer #4 · answered by SCI 2 · 0 0

distance formula is

d = sqrt[(x1-x2)^2 + (y1-y2)^2]

here x1 = 4, x2 = 6 , y1 = -1 , y2 = -7

d = sqrt[(4-6)^2 + (-1 -(-7)^2]

d = sqrt[(-2)^2 + (6)^2]

d = sqrt[4 + 36] = sqrt(40) = sqrt(2^2*10) = 2sqrt(10)

2007-12-25 13:28:07 · answer #5 · answered by mohanrao d 7 · 0 0

d ² = (6 - 4) ² + (- 7 + 1) ²
d ² = 2 ² + (- 6) ²
d ² = 4 + 36
d ² = 40
d = √40
d = 2√10

OPTION c.

2007-12-25 13:51:05 · answer #6 · answered by Como 7 · 2 0

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