OK let's clarify some things. You are asking for the "weight" of the Earth. Weight is the force of gravity on a body of mass m under the gravitational influence of a mass M. Newton's equation for this is F = GmM/R^2; where G is a constant and R is the distance between the weighed mass m and the mass M that is influencing m.
So the weight of Earth of mass m, under the gravitational influence of the Sun of mass M, is W = GmM/R^2; where R = 93 million miles give or take a few. Look up G, m, and M on the web and you can actually calculate the weight of Earth in pounds.
I suspect you really wanted to ask "what is the total mass of the planet Earth," which is quite a different question. Mass is independent of gravity. Mass is an intrinsic characteristic of matter because it's mass that gives inertia to objects. And with inertia, we have Newton's other three laws of inertia and force. You can find Earth's mass on the web.
Re Iron Mt. and Earth's rotation...Planet Earth of mass m is more or less a spheroid (actially it's an oblate spheroid) with radius R. And the angular momentum L = Iw; where I = 2/5 mR^2 for a sphere of uniform density (which Earth is not, but we'll assume it is). w is the angular velocity of the Earth's rotation, w = 2pi/24, which is one complete rotation (2pi radians) in 24 hours (i.e., a 24 hour day).
So your question is about w, the rate of rotation of Earth. Let's start with the conservation of angular momentum L. L remains fixed when no work is done on or by the rotating body. So we can write L = 2/5 mR^2 w = 2/5 .99999 m R^2 W = L' where L' is the angular momentum of a planet m whose mass was reduce by .0001%. W is the resulting angular velocity when the mass is removed.
Solving for W = w/.99999, which clearly shows that the angular velocity of the reduced mass planet is W > w [You can put your own reduction number in, but the result will be the same...angular velocity will increase.] So if you ejected Iron Mountain into space, the Earth's angular velocity would have to increase to conserve angular momentum Iw.
So the real reason I answered this question is to point out that weight and mass are not the same thing. Weight varies with the two masses and inversely with the square of the distances between them. Mass is an intrinsic value of all objects and it does not vary with gravity.
2007-12-25 05:13:33
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answer #1
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answered by oldprof 7
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Then don't forget to add back in all the weight from all the meteorites that hit the earth, etc. The items you list are not significant enough to change this number:
5.9736×10^24 kg That is a 5 with 24 more places to the left of the decimal....or 6 giga-tera tons of mass
2007-12-25 04:13:15
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answer #2
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answered by Charles M 6
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I extensively utilized to think of this, yet no. each thing this is supposedly 'guy-made' is in simple terms us employing the supplies on earth. all of the ingredients in contact in homes, machines etc have in simple terms been re-located. particularly than being deep in the floor, they're caught a million/2 way up a development. the internet weight of the Earth would not substitute by employing something substantial.
2016-11-24 23:37:32
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answer #3
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answered by santella 4
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very,very little effect. The iron ore didn't really go anywhere, it just got redistributed, and stuff in space is negligible compared to what hits us from outer space and what leaves naturally. The Earth is bigger than we are led to believe.
2007-12-25 03:42:39
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answer #4
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answered by hello 6
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when net mass is taken down from a mountain to a lower altitude it theoretically should make the earth spin faster. but in reality it doesnt because the mass moved is too small compared with the mass of the earth itslef and also because the distance moved is too small compared with the radius of the earth.
2007-12-25 03:53:38
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answer #5
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answered by Anonymous
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the weight of the earth is approximately 5.97 * 10 ^ 24 kg
the radius of the earth is 6580 km
distance of earth to the moon is 384, 400 km
added extra information=]
2007-12-25 10:49:50
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answer #6
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answered by Einstein Freak 2
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No weight change It is taken form the mine and used to make something else
2007-12-25 03:44:54
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answer #7
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answered by Anonymous
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Approximately 6,000,000,000,000,000,000,000,000 KG
2007-12-25 03:45:08
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answer #8
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answered by Ken C 2
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