i was wondering if there''ll be any reactions going in between BF3+NaF? since they both contain the same anion, if they do 'exchange anions and cations', wouldnt the product be the same? so is it right to say that as long as the cation/anion of two molecules is the same, no reaction will occur? eg between HCL and H20?
2007-12-24 18:38:31 · 2 answers · asked by blahhs 1 in Science & Mathematics ➔ Chemistry
Your first prediction is correct. No reaction can occur since the products would be identical to the reactants.
However you are incorrect with the reaction of HCl and H2O, since this is the textbook ionization of hydrogen chloride in water:
HCl(g) + H2O(l) -----> H3O+(aq) + Cl-(aq)
This reaction occurs since there is a decrease in energy of the system. It is exothermic.
2007-12-24 19:30:04 · answer #1 · answered by Dennis M 6 · 0⤊ 0⤋
Lots going on in this Q!
BF3 is polar covalent. If you write a Lewis structure with B-F single bonds, B has only 6 electrons. So it can readily react with many things that have lone pairs.
F- has a lone pair, and in fact NaF reacts with BF3 to make NaBF4. The BF4- anion is tetrahedral and isoelectronic with CF4.
HCl and water certainly do react, close to100% (HCl is a strong acid), to make H3O+ and Cl-.
You never really get free H+ in solution chemistry. In water, you should write it as H3O+.
2007-12-25 03:24:43 · answer #2 · answered by Facts Matter 7 · 0⤊ 0⤋