I am too! Just me and my beer!
2007-12-24 16:12:50
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answer #1
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answered by GasLight 4
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I am kind of... Spouse is working and doesn't celebrate holidays. I miss gathering with family, catching up on everything and the wonderful food.
For all you lonelies out there, you're not alone. Best to you all....
2007-12-25 01:26:32
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answer #2
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answered by Gimmemore 3
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I am. I think I'm alittle depressed. I can't be with the guy I like because he is detained. I seem to want to eat everything. I wish I could have slept through this weekend. [ at least sunday thru tuesday]
2007-12-25 00:20:15
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answer #3
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answered by Sparkeleyes 1
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Depends on what you mean by "alone". I am alone with my two teen boys that fight like cats and dogs most of the time.
Right now it is like a miracle has happened. They are actually getting along. I have my fingsers crossed.................
2007-12-25 00:12:24
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answer #4
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answered by Pixie 7
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"you" who? me? theres only one me. i wsh i could give you the exact number of lonelies for the christmas season. for the holidays i'm literally going to be on my hands and knees scrubbing the floor while my three brothers go to the ball. no joke.
2007-12-25 00:16:46
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answer #5
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answered by Anonymous
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I am taking care of a very ill relative, he doesn't even know I am here. I am doing it because his wife, who normally takes care of him, wanted to go visit friends for Christmas.
I might as well be by myself.
2007-12-25 00:22:15
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answer #6
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answered by Anonymous
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I am, but only because my Wife is with her parents out of state, they are older and really need her right now, so it's all good :)
2007-12-25 00:12:51
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answer #7
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answered by Life after 45 6
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Me cause mii family is n a different country....MERRY CHRISTMAS AND HAPPY HOLIDAYS <33
2007-12-25 00:12:40
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answer #8
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answered by Jewel 2
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If by alone you mean single, then I am.
2007-12-25 00:13:07
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answer #9
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answered by martymar1222 5
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Since I ran out of Viagra, I am!
2007-12-25 00:13:02
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answer #10
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answered by hardrider_x 2
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Not me this year. Merry christmas to all!
2007-12-25 00:16:55
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answer #11
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answered by Anonymous
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