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Calculate the amount (in mole) of:
1. Cl^- ions in 13.4g of nickel chloride(NiCl2)

2. O^2- ions in 159.7g of iron(iii) oxide (Fe2 O3)

Thanks

2007-12-24 14:57:01 · 4 answers · asked by Silver L 1 in Science & Mathematics Chemistry

4 answers

First determine the molar mass for nickel chloride:

58.71 + (2 x 35.45) = 129.61g/mole

Now find out how many moles you have:

13.4g/129.61 = 0.103moles

There are 2 chlorines per molecule of nickel chloride so there will be 2 x 0.103 moles or 0.206 moles Cl-1

It is done the same way for Iron (III) oxide; determine the weight per mole:

(2 x 55.85) + (3 x 16.00) = 159.7g/mole

Determine number of moles:

159.7g/159.7g/mole = 1.00mole

There are 3 O2- ions for each molecule so 3 x 1mole = 3 moles of O2- ions.

2007-12-24 16:37:55 · answer #1 · answered by Flying Dragon 7 · 0 2

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2016-05-17 12:09:47 · answer #2 · answered by Anonymous · 0 0

13.4g NiCl2 X 1mol/129.59g NiCl2 X 2molCl/1mol Ni

= 0.20681mol Cl(-)

Number two works the same way; by mol ratio.

I do not know which of you twits gave me a " thumbs down " for this correct answer and method, but this is highly unprofessional and should be kept to the ideological sites and out of science and math.

2007-12-24 16:26:50 · answer #3 · answered by Anonymous · 1 1

.21 mol Cl -

3 mol O-2

2007-12-24 16:30:05 · answer #4 · answered by archerpro101 3 · 0 1

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