how to do this algebra question..?

Question

4(x-5)(x+5) + 2(3x +2)^2

Answer 1

4(x-5)(x+5) + 2(3x +2)^2 is basically
4(x-5)(x+5) + 2(3x +2)(3x+2)

Expand the brackets first using FOIL or whichever method you prefer, so:
=4(x^2 - 25) + 2(9x^2 + 12x +4)
=4x^2 -100 + 18^2 +24x + 8
=22x^2 + 24x - 92

then you can use the quadratic formula to solve for x

Answer 2

Parentheses
Exponent
Division
Multiplication
Addition
Subtraction

use the PEDMAS method.
division and multiplication: doesn't matter which do you first.
and addition and subtraction: doesn't matter which you do first.
just do the multiplication and division before any subtraction and addition.

you do the exponent first.
(3x + 2)^2 = 9x^2 + 12x + 4

then distribute the 2.
2(9x^2 + 12x + 4) = 18x^2 + 24x + 8

then you work on the first part.
you can distribute the 4 into the first quantity or FOIL (first, outer, inner, last) the (x+5)(x-5).

but since the two quantities are also known as "a difference of two squares," i will do that first.

a difference of two squares can be something like (x+57)(x-57) or (x-2)(x+2) - as long is its 'minus X' in one quantity and 'plus X' in the other quantity. 'X' being any real number.

soo...
(x+5)(x-5) = x^2 - 25

then distribute the 4.
4 (x^2 - 25) = 4x^2 - 100

altogether you have...
4x^2 - 100 + 18x^2 + 24x + 8

then you combine like terms.
{4x^2} - [100] + {18x^2} + 24x + [8] = {4x^2 + 18x^2} + 24x [-100 + 8]
= 22x^2 + 24x - 92

and there you have it!

Answer 3

FOIL:
4(x * x + x * 5 - 5 * x - 5 * 5) + 2(3x + 2)^2

Simplify:
4(x^2 - 25) + 2(3x + 2)^2

Multiply 4 by each term:
(4(x^2) + 4 (-25)) + 2(3x + 2)^2

Keep going:
(4x^2 - 100) + 2(3x + 2)^2

FOIL again:
(4x^2 - 100) + 2(3x * 3x + 3x * 2 + 2 * 3x + 2 * 2)

Simplify:
(4x^2 - 100) + 2(9x^2 + 12x + 4)

Multiply by 2:
(4x^2 - 100) + (2(9x^2) + 2(12x) + 2(4))

Keep going:
4x^2 - 100 + 18x^2 + 24x + 8

Add 18x^2 to 4x^2 to get 22x^2 because they are like terms:
22x^2 + 24x - 100 + 8

Add 8 to -100
22x^2 + 24x - 92

Yeah, it doesn't look like an answer, but that's what they want.

Answer 4

First use the FOIL method to figure out the product of (x - 5)(x + 5)

x^2 + 5x - 5x - 25
x^2 - 25

Use the FOIL method to figure out the product of (3x + 2)^2.

(3x + 2)(3x + 2)
9x^2 + 6x + 6x + 4
9x^2 + 12x + 4

Now you have:

4(x^2 - 25) + 2(9x^2 + 12x + 4)

Distribute 4 into the first parenthesis and 2 into the second.

(4x^2 - 100) + (18x^2 + 24x + 8)

Rearrange the variables so that you can combine like-terms.

4x^2 + 18x^2 + 24x - 100 + 8
22x^2 + 24x - 92

So your answer is 22x^2 + 24x - 92.

Hope this helps!

Answer 5

Multiplye (x-5) times (x + 5) then multiply the result by four. Keep the result. Do (3x + 2)^2 then multiply the answer by 2. Add this result to the previous result. Done, at least I think so! ^_^

Answer 6

Multiply out the (x+5)(x+5) then distribute the four. Then square the (3x+2) and distribute the 2. Set equal to zero and solve. At least that's how I think you do it.

Answer 7

4(x -5)(x + 5) + 2(3x + 2)^2

4(x^2 + 5x - 5x - 25) + 2(9x^2 + 6x + 6x + 4)

4(x^2 - 25) + 2(9x^2 + 12x + 4)

4x^2 - 100 + 18x^2 + 24x + 8

22x^2 + 24x - 92

Answer 8

You would have to use the (Please Excuse My Dear Aunt Sally)

You would have to use the FOIL method...That means you would multiply the first two numbers (x*x)+(x*5)+(-5*x)(-5*5)

x2+5x+5x+25 = x2+10x-5x-25 = x2+5x-25

You will need to do the same with the 2(3x+2)^2

(3x+2)(3x+2)

9x2+6x+6x+4 = 9x2+12x+4

Then you have to distribute the 2 into the second part of the problem....2(9x2+12x+4)..Combine like values

18x2+24x+8

(x2+5x-25)+(18x2+24x+8)

Now you need to combine like values again

The answer will be

19x2+29x-17

Answer 9

is there:4(x-5)(x+5) + 2(3x +2)=2?
find x?

Answer 10

4(x--5)(x+5) + 2(3x+2)^2
= 4(x^2 --25) + 2(9x^2 + 12x + 4)
= 22x^2 + 24x -- 92