English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I cant seem to factor that looking for help =D

2007-12-24 05:36:56 · 5 answers · asked by Hershey 1 in Science & Mathematics Mathematics

5 answers

-2x^2 +4x +1
factorise using the formula for finding the roots
-b +/- sqrt b^2-4ac
x = ----------------------
2a

here a= -2, b=2, c=1

-4 +/- sqrt 16+8
x = -----------------------
-4

-4 +- 2 sqrt 6
= -----------------
-4

-2 (2-/+ sqrt 6)
= -------------------
-4
2 +/- sq rt 6
= --------------
2

so the factors are

2 +/- sqrt6
( x + ---------------)
2

2007-12-24 06:37:53 · answer #1 · answered by jaya 4 · 0 0

Using the Texas Instrument (TI-83) and the Y = editor we get a parabola downward. This appears to be a function with many (X,Y) values.

X Y Sorry,but I am not up to calculating with
-1 -15 quadratic formula.
0 1
3 -5

2007-12-24 05:55:00 · answer #2 · answered by gzlakewood@sbcglobal.net 4 · 0 0

I do not believe that it can be factored.
Quadratic Equation:
x = (-b ± √(b^2-4ac))/2a.
In your formula, a=-2, b=4, and c=1.
Therefore, x = (-4 ± √(16 + 8)) / -4.
The expression does not have a whole number answer.
Therefore, it cannot be factored.

2007-12-24 06:28:43 · answer #3 · answered by Richard A 2 · 0 0

since b^2 - 4ac is not a perfect sq, you have to use the quad formula to find the roots.

x = -(-4 +/- sqrt(24))/4

2007-12-24 05:44:18 · answer #4 · answered by norman 7 · 0 0

easy!
-2x^2+4x+1

find a number that multiplies to give -2
and adds to give +4

2007-12-24 06:53:02 · answer #5 · answered by (ƸӜƷ) 1 · 0 0

fedest.com, questions and answers