-2x^2 +4x +1
factorise using the formula for finding the roots
-b +/- sqrt b^2-4ac
x = ----------------------
2a
here a= -2, b=2, c=1
-4 +/- sqrt 16+8
x = -----------------------
-4
-4 +- 2 sqrt 6
= -----------------
-4
-2 (2-/+ sqrt 6)
= -------------------
-4
2 +/- sq rt 6
= --------------
2
so the factors are
2 +/- sqrt6
( x + ---------------)
2
2007-12-24 06:37:53
·
answer #1
·
answered by jaya 4
·
0⤊
0⤋
Using the Texas Instrument (TI-83) and the Y = editor we get a parabola downward. This appears to be a function with many (X,Y) values.
X Y Sorry,but I am not up to calculating with
-1 -15 quadratic formula.
0 1
3 -5
2007-12-24 05:55:00
·
answer #2
·
answered by gzlakewood@sbcglobal.net 4
·
0⤊
0⤋
I do not believe that it can be factored.
Quadratic Equation:
x = (-b ± â(b^2-4ac))/2a.
In your formula, a=-2, b=4, and c=1.
Therefore, x = (-4 ± â(16 + 8)) / -4.
The expression does not have a whole number answer.
Therefore, it cannot be factored.
2007-12-24 06:28:43
·
answer #3
·
answered by Richard A 2
·
0⤊
0⤋
since b^2 - 4ac is not a perfect sq, you have to use the quad formula to find the roots.
x = -(-4 +/- sqrt(24))/4
2007-12-24 05:44:18
·
answer #4
·
answered by norman 7
·
0⤊
0⤋
easy!
-2x^2+4x+1
find a number that multiplies to give -2
and adds to give +4
2007-12-24 06:53:02
·
answer #5
·
answered by (ƸӜƷ) 1
·
0⤊
0⤋